Hi these equations are from my notes for an exam, I have the equations but don't understand each step of how to derive the maximum force of the simple and cantilever beam or if there are any missing equations. Please could I have a written explanation of the derivations. Thank you. Maximum force applied to simple and Cantilever becameM = 61y6 = MyIy=1/12m 26. I:h:. m = 61(41)FL, 5bh²466=250MPam = 26K=Fuat 1/32 · asobh².MaxL→ Safety factor 2Fmax = 8bh²6L25ob h²F=500xFL22->>-=m = 26IhFouax /26bh²3bh2| →(Simple)3 2250bh (Cantilever)6LMaximum bendingSupports Cat both ends.m=FL4moments in a beam with

Answer In order to derive the maximum applied force 'F' we need to know about Bending equation…

Answered: how to derive the maximum force of the…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Hi these equations are from my notes for an exam, I have the equations but don't understand each step of how to derive the maximum force of the simple and cantilever beam or if there are any missing equations. Please could I have a written explanation of the derivations. Thank you.

Maximum force applied to simple and Cantilever became
M = 61
y
6 = My
I
y=1/12
m 26. I
:
h
:. m = 61
(41)
FL, 5bh²
4
6
6=250MPa
m = 26
K
=
Fuat 1/32 · asobh².
Max
L
→ Safety factor 2
Fmax = 8bh²
6L
25ob h²F=500x
FL
2
2->>
-
=
m = 26I
h
Fouax /2
6bh²
3
bh2| →(Simple)
3 2
250bh (Cantilever)
6L
Maximum bending
Supports Cat both ends.
m=FL
4
moments in a beam with

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