1. What is the f obtained for this problem?2.What is the f crit for this problem?3. F obtained is .. [not beyond or beyond] .. f crit, so we .. [fail to reject or reject].. the null hypothesis. Stress level makes.. [a significant difference or no significant difference] ..to decision making.4. Post hoc testing: What is the HSD for this problem?5.The difference between high stress and moderate stress is (significant or not significant)6. The difference between high stress and low stress is (significant or not significant)7.The difference between moderate stress and low stress is (significant or not significant)8. The effect size is ______. Computational Question BResearchers want to better understand the role of stress on decision making. They randomlyassigned subjects to one of three conditions: high stress, moderate stress and low stress. Afterapplying the varying levels of stressful conditions, subjects were measured on how well they madedecisions. Use the data below to complete the source table and form a conclusion to this researchquestion. Include the appropriate post hoc test and effect size. Use your calculations to answer thequestion.ModerateStressLow StressHigh Stress233661533.LO

Name: 1. What is the f obtained for this problem?2.What is the f crit for th
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Description: 1. What is the f obtained for this problem?2.What is the f crit for this problem?3. F obtained is .. [not beyond or beyond] .. f crit, so we .. [fail to reject or reject].. the null hypothesis. Stress level makes.. [a significant difference or no si

Note: Hi there! Thank you for posting the question. As your question has more than 3 parts, we have solved only the first three subparts for you. If you need any specific subpart to be answered, please re-submit the question by specifying the subpart number or name.(1). Find the F test statistic value: There are 3 treatment groups. The 3 treatment groups are High stress, Moderate stress and Low stress. Denote the true average for each of the 3 treatment groups as μ1, μ2, and μ3. The hypotheses to be tested are: Null hypothesis H0: H0: μ1 = μ2 = μ3. That is, the mean of all 3 treatment groups are equal. Alternative hypothesis H1: Ha: At least one of the mean of a group is different. That is, not all the population means are equal. Evidently, the test is for equality of 3 means. The means take numerical values. Now, a one-way ANOVA is the most suitable for testing the equality of several means, provided the assumptions of independence of observations, normality of residuals and homogeneity of variances are satisfied. The test is conducted here by using EXCEL. Software procedure: The step-by-step procedure to conduct the ANOVA test is given below: Enter the data of High stress, Moderate stress and Low stress in the columns A, B, and C. Select Data > Data Analysis > ANOVA: Single factor > OK. In Input Range enter $A$1:$C$7. In Grouped by select Click on Labels in First Row. Enter Alpha as 05 and click OK. The output using EXCEL is as follows: From the obtained ANOVA output, the value of test statistic is F = 10.3793.(2). Find the critical value of F: Since, the level of significance is not specified, the prior level of significance α = 0.05 can be used. From the obtained ANOVA output, the F critical value is F-critical = 3.6823. (3). Comment on the rejection of null hypothesis: Here, the F test statistic value is F = 10.3793. The F critical value is FCritical = 3.6823. Decision rule based on critical-value approach: If F ≥ Fcritical, then reject the null hypothesis H0. If F < Fcritical, then fail to reject the null hypothesis H0. The (= 0.764) is greater than the critical value (= 0.666). Here, 10.3793 (=test statistic-value) > 3.6823 (= critical value). Therefore, the null F obtained is beyond the F critical value. Hence, we reject the null hypothesis. Therefore, the stress levels makes a significant difference to decision making.