Required information NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. Consider the given figure. Given: P = 41 kN:m 15 kN/m 4.8 m 1.2 m Determine the magnitude and location of the maximum absolute value of the bending moment. |M|, |kN-m m from point A Imar X=

Q: 5. Find diameter y. All dimensions are in millimeters. 1 + 19.30 DIA 118.00 -३०

A: Tapered beam with larger diameter at AB = 19.3 mm  Length of beam ,L = 118 mm  Tapered angle = 3°…

Q: Compute Ix for the region shown. y 2 18 2-5--5- -2 -8 8. Dimensions in inches

A: The area is divided into the standard areas as shown below.

Q: 1. GIVEN: REQOIREO: yo l0". 7,9 to locete the centreid t 6"

A: To find centroid

Q: Describe briefly the T-v Diagram.

A: The TV diagram refers to the Temperature-Volume diagram for a particular substance. The diagram…

Q: Determine y for the area shown y 1" 1" in .5" 1" 2" 2" X

A:

Q: According to this figure, What is d? What is dt?

A: Draw the figure.

Q: [Choose ] solve equilibrium equations simultaneously ensure you have an equal number of unknowns and…

A: Understand force flow. Understand the math behind structural analysis (concepts like virtual work…

Q: How do I get the support forces

A: The x and y are the vertical and horizontal distances: x=12cos60=6 fty=6sin60=5.196 ft

Q: -0129 -077 R26

A:

Q: 4 cm 0 2 י 5 cm 4 567 Value: cm 10 5 150 Value: mm 0 140

A: There are two scales, and the values shown on the two scales are required.One is the main scale and…

Q: The block of mass m1 = m0 is attached to a spring of elastic constant k = (m0g)/H and natural length…

A:

Q: A Derive the equation for the unit influence line for the reaction at the support B in the…

A: By Muller Breslau method, remove Reaction at support B and place a Load of P as shown in figure. By…

Types of Composite

Composite materials are formed by merging two components that have different chemical and physical properties. The merged output is termed as a composite, whose properties are completely different from the individual components. Composite materials also have better strength than the individual components.Composite materials usually have two main parts, reinforcement material, and matrix material. The matrix material acts as a binder and surrounds the fiber of another material that bears a much higher strength. This material is known as the reinforcement material. The matrix materials are usually high-strength additives resins, while the fibers of the reinforced material can be random, oriented, and in a mat format.Composite materials are also known as fiber-reinforced composite polymers because they are composed of the polymer matrix which is reinforced to laboratory-created fibers or naturally occurring fibers, such as glass fibers, carbon fibers, or aramid fibers. Under the application of external loads, the matrix material absorbs and transfers the loads to the fibers, these fibers in return provide good compressive strength, tensile strength, and stiffness to the fiber-reinforced composite materials.Depending upon the matrix and the reinforcement material, different properties can be induced to the fiber-reinforced composite materials, including good corrosion resistance properties. The most common matrix material is the resin while the glass fibers act as the reinforcement material. Strong fibers provide strength and stiffness to the composite materials while, a soft and flexible resin provides shape to the composite materials.