Repeat the problem in Exercise 2 using the same lenses except for the following changes: (The exercise 2 is in the box below). (a) The second lens is a diverging lens having a focal length of magnitude 60.0 cm. (b) The first lens is a diverging lens having a focal length of magnitude 40.0 cm. (c) Both lenses are diverging lenses having focal lengths of the magnitudes as in problem Exercise 2. NOTE: The final answer should be (a) ?1=200 ??, (b) ?2′=−37.5 ??, ?2′=−1.80 ?? (c) The final image is ?′=37.5 cm to the left of the second lens, ?′=1.80 ??, inverted. EXERCISE 2: A 1.20-cm-tall object is 50.0 cm to the left of a converging lens of focal length 40.0 cm. A second converging lens, this one having a focal length of 60.0 cm, is located 300.0 cm to the right of the first lens along the same optic axis. (a) Find the location and height of the image (call it ?1) formed by the lens with a focal length of 40.0 cm. (b) ?1 is now the object for the second lens. Find the location and height of the image produced by the second lens. This is the final image produced by the combination of lenses.
Ray Optics
Optics is the study of light in the field of physics. It refers to the study and properties of light. Optical phenomena can be classified into three categories: ray optics, wave optics, and quantum optics. Geometrical optics, also known as ray optics, is an optics model that explains light propagation using rays. In an optical device, a ray is a direction along which light energy is transmitted from one point to another. Geometric optics assumes that waves (rays) move in straight lines before they reach a surface. When a ray collides with a surface, it can bounce back (reflect) or bend (refract), but it continues in a straight line. The laws of reflection and refraction are the fundamental laws of geometrical optics. Light is an electromagnetic wave with a wavelength that falls within the visible spectrum.
Converging Lens
Converging lens, also known as a convex lens, is thinner at the upper and lower edges and thicker at the center. The edges are curved outwards. This lens can converge a beam of parallel rays of light that is coming from outside and focus it on a point on the other side of the lens.
Plano-Convex Lens
To understand the topic well we will first break down the name of the topic, ‘Plano Convex lens’ into three separate words and look at them individually.
Lateral Magnification
In very simple terms, the same object can be viewed in enlarged versions of itself, which we call magnification. To rephrase, magnification is the ability to enlarge the image of an object without physically altering its dimensions and structure. This process is mainly done to get an even more detailed view of the object by scaling up the image. A lot of daily life examples for this can be the use of magnifying glasses, projectors, and microscopes in laboratories. This plays a vital role in the fields of research and development and to some extent even our daily lives; our daily activity of magnifying images and texts on our mobile screen for a better look is nothing other than magnification.
Repeat the problem in Exercise 2 using the same lenses except for the following changes: (The exercise 2 is in the box below).
(a) The second lens is a diverging lens having a focal length of magnitude 60.0 cm.
(b) The first lens is a diverging lens having a focal length of magnitude 40.0 cm.
(c) Both lenses are diverging lenses having focal lengths of the magnitudes as in problem Exercise 2.
NOTE: The final answer should be (a) ?1=200 ??, (b) ?2′=−37.5 ??, ?2′=−1.80 ?? (c) The final image is ?′=37.5 cm to the left of the second lens, ?′=1.80 ??, inverted.
| EXERCISE 2: A 1.20-cm-tall object is 50.0 cm to the left of a converging lens of focal length 40.0 cm. A second converging lens, this one having a focal length of 60.0 cm, is located 300.0 cm to the right of the first lens along the same optic axis. (a) Find the location and height of the image (call it ?1) formed by the lens with a focal length of 40.0 cm. (b) ?1 is now the object for the second lens. Find the location and height of the image produced by the second lens. This is the final image produced by the combination of lenses. |
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