• remove_from_list(my_list, indices): Takes two lists as input. Creates a new list from the first input list by removing the elements at indices given by the integers in the second input list, then return the new list. The indices in the second input list may have any order. For example, if the first input list is [4, 8, 12, 16], and the second input list is [0, 2], then the new list returned from the function should have the 4 and the 12 removed, because they were at indices 0 and 2 of the original list. Note: You do not need to consider negative indices for this function. > remove_from_list(['abc', 'def', 'ghi'], [1]) ['abc', 'ghi'] >>> strs = ['The', 'quick', 'brown', 'fox'] » remove_from_list(strs, [0, 3]) ['quick', 'brown'] >>> strs ['The', 'quick', 'brown', 'fox'] # original list is unchanged >> remove_from_list(['The', 'quick', 'brown', 'fox'], [3, 0]) ['quick', 'brown'] find last(my_list, x): Takes two inputs: the first being a list and the second being any type. Returns the index of the last element of the list which is equal to the second input; if it cannot be found, returns None instead. >> find_last(['a', 'b', 'b', 'a'], 'b') 2 >>» ind = find_last(['a', 'b', 'b', 'a'], 'c') >> print(ind) None find first(my_list, x): Takes two inputs: the first being a list and the second being any type. Returns the index of the first element of the list which is equal to the second input; if it cannot be found, returns None instead. >» find_first(['a', 'b', 'b', 'a'], 'b') 1 » ind = find_first(['a', 'b', 'b', 'a'], 'c') >> print(ind) None
• remove_from_list(my_list, indices): Takes two lists as input. Creates a new list from the first input list by removing the elements at indices given by the integers in the second input list, then return the new list. The indices in the second input list may have any order. For example, if the first input list is [4, 8, 12, 16], and the second input list is [0, 2], then the new list returned from the function should have the 4 and the 12 removed, because they were at indices 0 and 2 of the original list. Note: You do not need to consider negative indices for this function. > remove_from_list(['abc', 'def', 'ghi'], [1]) ['abc', 'ghi'] >>> strs = ['The', 'quick', 'brown', 'fox'] » remove_from_list(strs, [0, 3]) ['quick', 'brown'] >>> strs ['The', 'quick', 'brown', 'fox'] # original list is unchanged >> remove_from_list(['The', 'quick', 'brown', 'fox'], [3, 0]) ['quick', 'brown'] find last(my_list, x): Takes two inputs: the first being a list and the second being any type. Returns the index of the last element of the list which is equal to the second input; if it cannot be found, returns None instead. >> find_last(['a', 'b', 'b', 'a'], 'b') 2 >>» ind = find_last(['a', 'b', 'b', 'a'], 'c') >> print(ind) None find first(my_list, x): Takes two inputs: the first being a list and the second being any type. Returns the index of the first element of the list which is equal to the second input; if it cannot be found, returns None instead. >» find_first(['a', 'b', 'b', 'a'], 'b') 1 » ind = find_first(['a', 'b', 'b', 'a'], 'c') >> print(ind) None
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
Related questions
Question
![remove_from_list(my_list, indices): Takes two lists as input. Creates a new list from the first
input list by removing the elements at indices given by the integers in the second input list, then
return the new list. The indices in the second input list may have any order.
For example, if the first input list is [4, 8, 12, 161, and the second input list is [0, 2], then the
new list returned from the function should have the 4 and the 12 removed, because they were at
indices 0 and 2 of the original list.
Note: You do not need to consider negative indices for this function.
>> remove_from_list(['abc', 'def', 'ghi'], [1])
['abc', 'ghi']
>>> strs =
['The', 'quick', 'brown', 'fox']
>>> remove_from_list(strs, [0, 3])
['quick', 'brown']
>>> strs
['The', 'quick', 'brown', 'fox'] # original list is unchanged
>> remove_from_list(['The', 'quick', 'brown', 'fox'], [3, 0])
['quick', 'brown']
find_last(my_list, x): Takes two inputs: the first being a list and the second being any type.
Returns the index of the last element of the list which is equal to the second input; if it cannot be
found, returns None instead.
>» find_last(['a', 'b', 'b', 'a'], 'b')
2
>>» ind = find_last(['a', 'b', 'b', 'a'], 'c')
>>» print(ind)
None
• find_first(my_list, x): Takes two inputs: the first being a list and the second being any type.
Returns the index of the first element of the list which is equal to the second input; if it cannot be
found, returns None instead.
>> find_first(['a', 'b', 'b', 'a'], 'b')
1
>» ind = find_first(['a', 'b', 'b', 'a'], 'c')
>>» print(ind)
None](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ffa39c2fc-1c0d-4f85-bcf9-bc7e900ecb05%2F2f8318d7-8c2d-4eae-aca6-d208a14d16a4%2Fool0h3_processed.jpeg&w=3840&q=75)
Transcribed Image Text:remove_from_list(my_list, indices): Takes two lists as input. Creates a new list from the first
input list by removing the elements at indices given by the integers in the second input list, then
return the new list. The indices in the second input list may have any order.
For example, if the first input list is [4, 8, 12, 161, and the second input list is [0, 2], then the
new list returned from the function should have the 4 and the 12 removed, because they were at
indices 0 and 2 of the original list.
Note: You do not need to consider negative indices for this function.
>> remove_from_list(['abc', 'def', 'ghi'], [1])
['abc', 'ghi']
>>> strs =
['The', 'quick', 'brown', 'fox']
>>> remove_from_list(strs, [0, 3])
['quick', 'brown']
>>> strs
['The', 'quick', 'brown', 'fox'] # original list is unchanged
>> remove_from_list(['The', 'quick', 'brown', 'fox'], [3, 0])
['quick', 'brown']
find_last(my_list, x): Takes two inputs: the first being a list and the second being any type.
Returns the index of the last element of the list which is equal to the second input; if it cannot be
found, returns None instead.
>» find_last(['a', 'b', 'b', 'a'], 'b')
2
>>» ind = find_last(['a', 'b', 'b', 'a'], 'c')
>>» print(ind)
None
• find_first(my_list, x): Takes two inputs: the first being a list and the second being any type.
Returns the index of the first element of the list which is equal to the second input; if it cannot be
found, returns None instead.
>> find_first(['a', 'b', 'b', 'a'], 'b')
1
>» ind = find_first(['a', 'b', 'b', 'a'], 'c')
>>» print(ind)
None
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