Remember graph coloring problem in the problem session. (a) Draw the graph of the following code block. (b) Explain how you represent the components of the code in graph coloring problem. (c) What is the minimum number of registers that you need to compile the code? Show which variables can be in the same register. Line 1: a = 3 Line 2: b = 6 Line 3: c = 4 Line 4: d = b + c Line 5: e = d + a Line 6: if e < 4 then f = 4  b Line 7: else then f = 6  a Line 8: d = f - c

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
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Remember graph coloring problem in the problem session.
(a) Draw the graph of the following code block.
(b) Explain how you represent the components of the code in graph coloring problem.
(c) What is the minimum number of registers that you need to compile the code? Show which variables can be
in the same register.
Line 1: a = 3
Line 2: b = 6
Line 3: c = 4
Line 4: d = b + c
Line 5: e = d + a
Line 6: if e < 4 then f = 4  b
Line 7: else then f = 6  a
Line 8: d = f - c

Remember graph coloring problem in the problem session.
(a) Draw the graph of the following code block.
(b) Explain how you represent the components of the code in graph coloring problern.
(c) What is the minimum number of registers that you need to compile the code? Show which variables can be
in the same register.
Line 1: a= 3
Line 2: b = 6
Line 3: c = 4
Line 4: d = b+e
Line 5: e = d + a
Line 6: if e < 4 then f= 4 x b
Line 7: else then f = 6 x a
Line 8: d = f-e
Transcribed Image Text:Remember graph coloring problem in the problem session. (a) Draw the graph of the following code block. (b) Explain how you represent the components of the code in graph coloring problern. (c) What is the minimum number of registers that you need to compile the code? Show which variables can be in the same register. Line 1: a= 3 Line 2: b = 6 Line 3: c = 4 Line 4: d = b+e Line 5: e = d + a Line 6: if e < 4 then f= 4 x b Line 7: else then f = 6 x a Line 8: d = f-e
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