Remaining Time: 1 hour, 29 minutes, 21 seconds.Question Completion Status:Analyze the following code. We want to remove the node hary. what code to apply ?Node tomNode dickNode harry= new Node("Tom", null);= new Node("Dick", null);= new Node("Harry", null);Node sam = new Node("Sam", null);Node headdick;harry;tom;tom.nextdick.next =harry.nextsam;%3DO dick.next.next = dick.nextO dick= harry.nextO harry.next = harry.next.next;O dick novt - dick novt noutClick Save and Submit to save and submit. Click Save All Answers to save all answers.Save All AnswersClose Windowexercice3.docxexercice2.docxTOSHIBA近

Remaining Time: 1 hour, 29 minutes, 21 seconds. Question Completion Status: Analyze the following code. We want to remove the node harry. what code to apply ? Node tom = new Node("Tom", null); Node dick = new Node("Dick", null); Node harry Node sam = new Node("Sam", null); Node head = new Node("Harry", null); tom; dick; harry; tom.next dick.next = harry.next = sam;

Remaining Time: 1 hour, 29 minutes, 21 seconds. Question Completion Status: Analyze the following code. We want to remove the node harry. what code to apply ? Node tom = new Node("Tom", null); Node dick = new Node("Dick", null); Node harry Node sam = new Node("Sam", null); Node head = new Node("Harry", null); tom; dick; harry; tom.next dick.next = harry.next = sam;

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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B4.In double-linked list, assume head references the first list node and tail references the last list node. Write the sample of code to insert a node "Ahmed" in between Ayan and Asma. Node Node Node next - nu11 prev - data -"Asma" next - next - prev - nu11 data - "sara" prev - "Ayan" data -
C++ please Please complete Programming Exercise 4, from pages 1402, from chapter 19 from your textbook. Write a function, singleParent, that returns the number of nodes in abinary tree that have only one child. Add this function to the classbinaryTreeType and create a program to test this function. (Note: Firstcreate a binary search tree.)
THIS IS MY CODE HELP ME ACHIEVE POINTS OUTLINED BELOW : #include <stdio.h>#include <stdlib.h>#include <string.h>#include <float.h>#include "graph.h"#include "dijkstra.h" #define INFINITY DBL_MAX /* find shortest paths between source node id and all other nodes in graph. *//* upon success, returns an array containing a table of shortest paths. *//* return NULL if *graph is uninitialised or an error occurs. *//* each entry of the table array should be a Path *//* structure containing the path information for the shortest path between *//* the source node and every node in the graph. If no path exists to a *//* particular desination node, then next should be set to -1 and weight *//* to DBL_MAX in the Path structure for this node */Path *dijkstra(Graph *graph, int id, int *pnEntries){ int n; int i, j; int* nv = get_vertices(graph, &n); int *S = malloc(n * sizeof(int)); double *D = malloc(n * sizeof(double)); int *R = malloc(n…
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In this code: #include <iostream> #include <string> using namespace std;// Node struct to store data for each song in the playliststruct Node { string data; Node * next;};// Function to create a new node and return its addressNode * getNewNode(string song) { Node * newNode = new Node(); newNode -> data = song; newNode -> next = NULL; return newNode;}// Function to insert a new node at the head of the linked listvoid insertAtHead(Node ** head, string song) { Node * newNode = getNewNode(song); if ( * head == NULL) { * head = newNode; return;} newNode -> next = * head; * head = newNode;}// Function to insert a new node at the tail of the linked listvoid insertAtTail(Node ** head, string song) { Node * newNode = getNewNode(song); if ( * head == NULL) { * head = newNode; return; } Node * temp = * head; while (temp -> next != NULL) { temp = temp -> next; } temp -> next = newNode;}// Function to remove a node from the linked listvoid removeNode(Node ** head,…
bool DelOddCopEven(Node* headPtr) { if (headPtr == nullptr) { return false; } Node* prev = nullptr; Node* current = headPtr; while (current != nullptr) { if (current->data % 2 != 0) { // Odd-valued node, delete it if (prev != nullptr) { prev->link = current->link; } else { headPtr = current->link; } Node* temp = current; current = current->link; delete temp; } else { // Even-valued node, create a copy and insert it after the original node Node* newNode = new Node; newNode->data = current->data; newNode->link = current->link; current->link = newNode; // Update the previous and current pointers prev = newNode; current = newNode->link; } } return true;} int FindListLength(Node* headPtr){ int length = 0;…
Question 5 what does the following method do? private void reOrder (Node node) { if (node == null) return; else { reOrder (node.left); reorder (node.right); System.out.print (node.data + " "); } } (A) getLeft Subtree B) postOrder Traverse c) inOrder Traverse preorder Traverse
Question 3 public E unknown() { Node pt1,pt2; if (head != null) { pt1=head; pt2= getNode(size-1); if (pt1.data.equals(pt2.data)) return getNode(size/2).data; else return pt1.data; } A It returns half of the data of the last node in the list or the data of the first node B It returns half of the data of the last node in the list or the data of the last node in the list C It returns the data of the middle node in the list or the data of the first node It returns the data of the middle node in the list or the data of the last node in the list
Node* temp=new node(); if(temp==0) return 0; return 1; we can use this to check if the linked queue is full or not Select one: True False
//Can you explain how this code work or the meaning of this code?#include <iostream>using namespace std;struct Node {int data;struct Node *next;};struct Node* head = NULL;struct Node* rhead = NULL;int count1;//insert at front for reverselistvoid insertfront(int data){Node* new_node = (Node*) malloc(sizeof(Node)); new_node->data = data; new_node->next = rhead; rhead=new_node;}//insert at endvoid insert(int new_data){Node* ptr;ptr = head;Node* new_node = (Node*) malloc(sizeof(Node)); new_node->data = new_data; new_node->next = NULL;if (head == NULL) { head = new_node; } else{while (ptr->next!= NULL) { ptr = ptr->next;}ptr->next=new_node;}count1++;}//display listvoid display() {struct Node* ptr;ptr = head;if(head==NULL){cout<<"Sorry the list is empty";return;}while (ptr != NULL) {cout<< ptr->data <<" ";ptr = ptr->next;}cout<<endl;}//delete datavoid deletedata(int data){Node* ptr,*ptrpre;ptr = head;if (head == NULL) {…
Fix the main file errors. public void Insert(int newItem) { Node parent = null; Node newNode = new Node(newItem); Node current = root; while (current != null) { parent = current; if (newNode.item < current.item) { current = current.Left; } else { current = current.Right; } } if (root == null) { root = newNode; } else { if (newNode.item < parent.item) { parent.Left = newNode; } else { parent.Right = newNode; } } } private int getHeight(){ return findHeight(root); } private int findHeight(Node root){ if(root==null){ return 0; } int leftHeight = findHeight(root.Left); int rightHeight = findHeight(root.Right); return Math.max(leftHeight,rightHeight)+1; } private int getLargestKey(){…
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