Question 5 what does the following method do? private void reOrder (Node node) { if (node == null) return; else { reOrder (node.left); reOrder (node.right); System.out.print (node.data + " "); } } A getLeft Subtree.
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- What does mystryMethod ( ) do? void mystryMethod (Node n, int vall, int val2) { if (n.data vall){ == Node node new Node (val2); node.next = n.next; n.next node; return; } mystryMethod(n.next, vall,val2); }Please fill in the code gaps if possible. This problem has been giving me trouble. Any help is appreciated. public class Node { private String element; // we assume elements are character strings private Node next; /* Creates a node with the given element and next node. */ public Node(String s, Node n) { //fill in body } /* Returns the element of this node. */ public String getElement() { //fill in body } /* Returns the next node of this node. */ public Node getNext() { //fill in body } // Modifier methods: /* Sets the element of this node. */ public void setElement(String newElem) { //fill in body } /* Sets the next node of this node. */ public void setNext(Node newNext) { //fill in body } }class BSTNode { int key; BSTNode left, right; public BSTNode(int item) { key = item; left = right = null; } } class BST_Tree { BSTNode root; BST_Tree() { // Constructor root = null; } boolean search(int key){ return (searchRec(root, key) != null); } public BSTNode searchRec(BSTNode root, int key) { if (root==null || root.key==key) return root; if (root.key > key) return searchRec(root.left, key); return searchRec (root.right, key); } void deleteKey(int key) { root = deleteRec(root, key); } /* A recursive function to insert a new key in BST */ BSTNode deleteRec(BSTNode root, int key) { /* Base Case: If the tree is empty */ if (root == null) return root; /* Otherwise, recur down the tree */ if (key < root.key)…
- Queue q= new LinkedQueue (8); q.enqueue ("A"); q.enqueue ("B"); q.enqueue ("C"); q.enqueue ("D"); q.enqueue ("E"); q.enqueue ("F"); Stack s= new LinkedStack (8); for (int i=0; i<3; i++) { s.push (q.de queue () ); After all of this code executes, the size of the queue g is -----and the size of the stack is ------ 1, 5 3, 3 4. 2 5, 1A Dictionary implementation using Binary Search Trees Program requirements and structure You should be able to do the following: Add dictionary entries Search for an entry Print the whole dictionary You will be using the .compareTo method from the String class in order to move through your tree. Recursive method to print the tree in inorder traversal (you need little mods below code) public void printTree(Node root){ if(root != null){ printTree(root.getLeftChild()); System.out.println(root.toSting( )); printTree(root.getRightChild()); } } Instructions: Please use CODE TEMPLATE!in C++, create a binary search tree class using the class templatr below. class BinarySearchTree{ public:BinarySearchTree(); ~BinarySearchTree(); const int & findMin() const; const int & findMax() const; bool contains(cons tint &x) const; bool isEmpty(); void insert(const int &x); void remove(const int &x); private: struct BinaryNode{ int element; BinaryNode *left; BinaryNode *right; BinaryNode(const int &el, BinaryNode *lt, BinaryNode *rt) :element(el), left(lt), right(rt){} }; BinaryNode *root; void insert(const int &x, BinaryNode *&t) const; void remove(const int &x, BinaryNode *&t) const; BinaryNode * findMin(BinaryNode *t) const; BinaryNode * findMax(BinaryNode *t) const; bool contains(cons tint &x, BinaryNode *t) const; };
- class BSTNode { int key; BSTNode left, right; public BSTNode(int item) { key = item; left = right = null; } } class BST_Tree { BSTNode root; BST_Tree() { // Constructor root = null; } boolean search(int key){ return (searchRec(root, key) != null); } public BSTNode searchRec(BSTNode root, int key) { if (root==null || root.key==key) return root; if (root.key > key) return searchRec(root.left, key); return searchRec (root.right, key); } void deleteKey(int key) { root = deleteRec(root, key); } /* A recursive function to insert a new key in BST */ BSTNode deleteRec(BSTNode root, int key) { /* Base Case: If the tree is empty */ if (root == null) return root; /* Otherwise, recur down the tree */ if (key < root.key)…Question 3 public E unknown() { Node pt1,pt2; if (head != null) { pt1=head; pt2= getNode(size-1); if (pt1.data.equals(pt2.data)) return getNode(size/2).data; else return pt1.data; } A It returns half of the data of the last node in the list or the data of the first node B It returns half of the data of the last node in the list or the data of the last node in the list C It returns the data of the middle node in the list or the data of the first node It returns the data of the middle node in the list or the data of the last node in the listTree.java: This is a simple binary tree class that should be used to represent the data in your Huffman tree. You only need to implement two of the methods (_printTree and compareTo). Huffman.java: This file contains all of the logic required to implement a Huffman tree. The code in this file relies on the Tree.java file. You must provide the implementation for all of the methods in this class. public class Main { /* * tree.txt should produce this tree: * 16 * / \ * 6 Z * / \ * A D * * A (1), D (5), Z (10) * * Codes: * A: 00 * D: 01 * Z: 1 * * Preorder Traversal: * 16, 6, 1 (A), 5 (D), 10 (Z) */ public static void main(String[] args) throws Exception { Huffman huff = new Huffman(); huff.buildTreeFromFile("tree.txt"); // Print the tree: System.out.println("printTree tests:"); huff.printTree(); // Expected output: [16: , 6: , 1:A, 5:D, 10:Z] // Get some codes:…
- Explain the following code : public static void printLeafNodes(TreeNode node) { // base case if (node == null) { return; } if (node.left == null && node.right == null) { System.out.printf("%d ", node.value); } printLeafNodes(node.left); printLeafNodes(node.right); }Fix the main file errors. public void Insert(int newItem) { Node parent = null; Node newNode = new Node(newItem); Node current = root; while (current != null) { parent = current; if (newNode.item < current.item) { current = current.Left; } else { current = current.Right; } } if (root == null) { root = newNode; } else { if (newNode.item < parent.item) { parent.Left = newNode; } else { parent.Right = newNode; } } } private int getHeight(){ return findHeight(root); } private int findHeight(Node root){ if(root==null){ return 0; } int leftHeight = findHeight(root.Left); int rightHeight = findHeight(root.Right); return Math.max(leftHeight,rightHeight)+1; } private int getLargestKey(){…