**Title: Understanding Basic Heat Exchanger Dynamics****Diagram Overview:**The diagram represents a heat exchanger system involving air and refrigerant R134a. **System Description:**1. **Inlet and Outlet Flows:** - Air enters the heat exchanger at point 1 and exits at point 2. - Refrigerant R134a enters at point 3 and exits at point 4.**Given Conditions:**- **Assumptions:** - Kinetic energy and potential energy are considered negligible. - The system is in a steady state.- **Measurements:** - **Point 1 (Air Inlet):** - Pressure (P₁) = 1 Bar - Temperature (T₁) = 89.6°F - Volume flow rate (Av₁) = 1 m³/s - **Point 2 (Air Outlet):** - Pressure (P₂) = 0.95 Bar - Temperature (T₂) = 71.6°F - **Point 3 (Refrigerant Inlet):** - Pressure (P₃) = 5 Bar - Quality (x₃) = 0.2 - **Point 4 (Refrigerant Outlet):** - Pressure (P₄) = 5 Bar - Temperature (T₄) = 68°F**Objective:**- **Determine the following:** 1. Mass flow rate of refrigerant R134a in kg/s. 2. Heat transfer rate between refrigerant R134a and air.This setup provides a fundamental analysis of a heat exchanger's performance, necessary for understanding thermodynamic processes in cooling and heating systems.

Given:Inlet air condition, P1= 1 Bar, T1=89.6o F, AV1=1 m3/sOutlet air condition, P2=0.95 Bar,…

REFRIGERANT 134 a Ask 3 : HEAT EXCHANGER AIR GIVEN : KINETIC ENERGY STEADY STATE 2 AIR > 4 REFRIGERANT 134 a AND POTENTIAL 1) FLOW RATE MASS 2) HEAT TRANSFER RATE and REFRIGERANT 134 a 0 P₁ = 1 T₁ (AV₁) = 1m³/s 1 Bar @ P2 = 89,6 F = 0.95 Bar 71.6°F T₂ = OF REFRIGE RANT ENERGY = 0 AIR. 1349 BETWEEN P3 3 = 5 Bar IN kg/s 0.2 41 P4 = 5 Bar T4= 68°F

REFRIGERANT 134 a Ask 3 : HEAT EXCHANGER AIR GIVEN : KINETIC ENERGY STEADY STATE 2 AIR > 4 REFRIGERANT 134 a AND POTENTIAL 1) FLOW RATE MASS 2) HEAT TRANSFER RATE and REFRIGERANT 134 a 0 P₁ = 1 T₁ (AV₁) = 1m³/s 1 Bar @ P2 = 89,6 F = 0.95 Bar 71.6°F T₂ = OF REFRIGE RANT ENERGY = 0 AIR. 1349 BETWEEN P3 3 = 5 Bar IN kg/s 0.2 41 P4 = 5 Bar T4= 68°F

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

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Question

**Title: Understanding Basic Heat Exchanger Dynamics**

**Diagram Overview:**
The diagram represents a heat exchanger system involving air and refrigerant R134a.

**System Description:**
1. **Inlet and Outlet Flows:**
- Air enters the heat exchanger at point 1 and exits at point 2.
- Refrigerant R134a enters at point 3 and exits at point 4.

**Given Conditions:**
- **Assumptions:**
- Kinetic energy and potential energy are considered negligible.
- The system is in a steady state.

- **Measurements:**
- **Point 1 (Air Inlet):**
- Pressure (P₁) = 1 Bar
- Temperature (T₁) = 89.6°F
- Volume flow rate (Av₁) = 1 m³/s
- **Point 2 (Air Outlet):**
- Pressure (P₂) = 0.95 Bar
- Temperature (T₂) = 71.6°F
- **Point 3 (Refrigerant Inlet):**
- Pressure (P₃) = 5 Bar
- Quality (x₃) = 0.2
- **Point 4 (Refrigerant Outlet):**
- Pressure (P₄) = 5 Bar
- Temperature (T₄) = 68°F

**Objective:**
- **Determine the following:**
1. Mass flow rate of refrigerant R134a in kg/s.
2. Heat transfer rate between refrigerant R134a and air.

This setup provides a fundamental analysis of a heat exchanger's performance, necessary for understanding thermodynamic processes in cooling and heating systems.

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