Referring to the binary search tree below, select the correct choice for each of the following dropdowns: • The level of A is [Select ] The height of the tree is [ Select ] • The level of P is [Select ] NOTE: in case the below image does not show in your browser, the tree looks like: root ------> A В FX /\ /|\| с THQ z P root В F C T

Referring to the binary search tree below, select the correct choice for each of the following dropdowns: • The level of A is [Select ] The height of the tree is [ Select ] • The level of P is [Select ] NOTE: in case the below image does not show in your browser, the tree looks like: root ------> A В FX /\ /|\| с THQ z P root В F C T

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Ex1. DLL2BST Add a constructor that constructs the binary search tree from the given DLList. BST<T>::BST(const DLL<T>& list)
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Tree: For the following Binary Search (37,24,35,53,55,65,69) of root 37, if you add the item 63 to the tree, the postorder traversal will be: 35, 24, 63, 69, 65, 55, 53, 37 O24, 35, 37, 55, 53, 63, 65, 69 Skip O 35, 24, 65, 69, 63, 55, 53, 37 O24, 37, 35, 53, 55, 63, 65, 69
You have the following Binary Search Tree. After the insertion of 12, 24, 81, what will be the elements in the leaf node?* 11, 32, 50, 72, 99 12, 24, 32, 50, 81, 99 11, 12, 24, 81, 32, 50, 72, 99 12, 24, 81 12, 20, 24, 32, 50, 72, 99
bool DelOddCopEven(Node* headPtr) { if (headPtr == nullptr) { return false; } Node* prev = nullptr; Node* current = headPtr; while (current != nullptr) { if (current->data % 2 != 0) { // Odd-valued node, delete it if (prev != nullptr) { prev->link = current->link; } else { headPtr = current->link; } Node* temp = current; current = current->link; delete temp; } else { // Even-valued node, create a copy and insert it after the original node Node* newNode = new Node; newNode->data = current->data; newNode->link = current->link; current->link = newNode; // Update the previous and current pointers prev = newNode; current = newNode->link; } } return true;} int FindListLength(Node* headPtr){ int length = 0;…
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Write the following string with your information: string=”your fullName 19-arid-yourNo” //e.g.Isha Tir Razia 19-ARID-1098 //consider & use space after each word Now draw a Huffman tree and generate codes.
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