Refer to these values from the previous step. N = 13, M = 7, n = 6, k = 5, NM = 6, n - k = 1 Substitute these values into the hypergeometric probability formula, or use technology. Round your answer to four decimal places. CMC-k N-M P(x = k) = P(x = 5) = c57C₁6 13 N Therefore, the probability of selecting five brown and one red M&Ms from a candy dish containing seven brown and six red M&Ms is

MATLAB: An Introduction with Applications
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Step 5

Step 4
Using the values we have previously determined, N = 13, M = 7, n = 6, and k = 5. The remaining values needed for the formula are N - M and n-
k.
Find N - M.
NM 13 - 7
=
Find n - k.
n-k= 6-5
=
Step 5
Refer to these values from the previous step.
P(x = k)
N = 13, M = 7, n = 6, k = 5, N - M = 6, n - k = 1
Substitute these values into the hypergeometric probability formula, or use technology. Round your answer to four decimal places.
N - M
CKMC
P(x = 5)
=
=
=
6
1
C57C₁6
13
C6²
'n-k
N
C
Therefore, the probability of selecting five brown and one red M&Ms from a candy dish containing seven brown and six red M&Ms is
Transcribed Image Text:Step 4 Using the values we have previously determined, N = 13, M = 7, n = 6, and k = 5. The remaining values needed for the formula are N - M and n- k. Find N - M. NM 13 - 7 = Find n - k. n-k= 6-5 = Step 5 Refer to these values from the previous step. P(x = k) N = 13, M = 7, n = 6, k = 5, N - M = 6, n - k = 1 Substitute these values into the hypergeometric probability formula, or use technology. Round your answer to four decimal places. N - M CKMC P(x = 5) = = = 6 1 C57C₁6 13 C6² 'n-k N C Therefore, the probability of selecting five brown and one red M&Ms from a candy dish containing seven brown and six red M&Ms is
Tutorial Exercise
A candy dish contains seven brown and six red M&Ms. A child selects six M&Ms without checking the colors.
What is the probability that there are five brown and one red M&Ms in the selection?
Step 1
Begin by confirming that the hypergeometric distribution is appropriate for this sample. We check that ≥ 0.05, where n = 6 is the number of M&Ms being selected and N = 13 is the total number of M&Ms in the bowl. (Round your answ
two decimal places.)
N
6
13
n
N
= 0.46
n
The ratio is
N
0.46
is greater than 0.05, so we can
Step 2
Recall that for a hypergeometric distribution, the population contains M successes and N
P(x = k) =
Given a total of seven brown and six red M&Ms in the dish, the total number of M&Ms is N = 13
CKMCn-k
C₂
can use the hypergeometric probability distribution.
Step 3
Refer to the formula for the probability of exactly k successes in a random sample of size n below.
N - M
N
-
Thus, in the sample of size n = 6
M failures. Consider drawing a brown M&M to be a success and a red M&M to be a failure.
I
With seven brown M&Ms in a bowl of thirteen M&Ms, we have already determined M = 7 and N = 13. The remaining variables are k and n. We are told that six M&Ms are drawn, and we are calculating the probability of exactly five brown
M&Ms, or five successes, from that sample of six.
13 and the total successes (or brown M&Ms) is M =
the number of successes, or brown M&Ms, is k =
5
Transcribed Image Text:Tutorial Exercise A candy dish contains seven brown and six red M&Ms. A child selects six M&Ms without checking the colors. What is the probability that there are five brown and one red M&Ms in the selection? Step 1 Begin by confirming that the hypergeometric distribution is appropriate for this sample. We check that ≥ 0.05, where n = 6 is the number of M&Ms being selected and N = 13 is the total number of M&Ms in the bowl. (Round your answ two decimal places.) N 6 13 n N = 0.46 n The ratio is N 0.46 is greater than 0.05, so we can Step 2 Recall that for a hypergeometric distribution, the population contains M successes and N P(x = k) = Given a total of seven brown and six red M&Ms in the dish, the total number of M&Ms is N = 13 CKMCn-k C₂ can use the hypergeometric probability distribution. Step 3 Refer to the formula for the probability of exactly k successes in a random sample of size n below. N - M N - Thus, in the sample of size n = 6 M failures. Consider drawing a brown M&M to be a success and a red M&M to be a failure. I With seven brown M&Ms in a bowl of thirteen M&Ms, we have already determined M = 7 and N = 13. The remaining variables are k and n. We are told that six M&Ms are drawn, and we are calculating the probability of exactly five brown M&Ms, or five successes, from that sample of six. 13 and the total successes (or brown M&Ms) is M = the number of successes, or brown M&Ms, is k = 5
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