Refer to the following standard reduction half-cell potentials at 25° C: Ni?+ (aq) + 2e VO2 (aq) + 2H*(aq) + → Ni(s) → VO² (aq) + H2O(1) E° = -0.23 V e E° = 0.99 V Part A An electrochemical cell is based on these two half-reactions: Ni(s) → Ni²+ (aq, 2.5M) +2e Reduction: VO2 *(aq, 0.031M) + 2H*(aq, 1.1M) + e → VO²*(aq, 2.5M) + H2O(1) Oxidation: Calculate the cell potential. Express your answer to two decimal places and include the appropriate units.

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Refer to the following standard reduction half-cell potentials at 25° C:
Ni?+ (aq) + 2e
+ Ni(s)
- VO²+ (aq) + H2O(1)
E° = -0.23 V
VO, + (aq) + 2H*(aq)
E° = 0.99 V
e
Part A
An electrochemical cell is based on these two half-reactions:
Ni(s) → Ni²+ (aq, 2.5M) + 2e
Reduction: VO, *(aq, 0.031M) + 2H*(aq, 1.1M) +e → VO²+ (aq, 2.5M) + H2O(1)
Oxidation:
Calculate the cell potential.
Express your answer to two decimal places and include the appropriate units.
Transcribed Image Text:Refer to the following standard reduction half-cell potentials at 25° C: Ni?+ (aq) + 2e + Ni(s) - VO²+ (aq) + H2O(1) E° = -0.23 V VO, + (aq) + 2H*(aq) E° = 0.99 V e Part A An electrochemical cell is based on these two half-reactions: Ni(s) → Ni²+ (aq, 2.5M) + 2e Reduction: VO, *(aq, 0.031M) + 2H*(aq, 1.1M) +e → VO²+ (aq, 2.5M) + H2O(1) Oxidation: Calculate the cell potential. Express your answer to two decimal places and include the appropriate units.
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