### Problem DescriptionRefer to the figure. Let the mass of the block be 5.90 kg and the angle \( \theta \) be 29.0°. 1. **(a)** Find the tension in the cord.2. **(b)** Find the normal force acting on the block.3. **(c)** If the cord is cut, find the magnitude of the block's acceleration.### Diagram Description#### Diagram (a)This is a side view schematic diagram showing a block of mass \( m \) resting on a frictionless inclined plane. The angle of inclination is \( \theta \). A cord is attached to the block and supports it as it lies against a vertical wall.#### Diagram (b)A free-body diagram showing the forces acting on the block:- \( \vec{F}_{N} \): The normal force acting perpendicular to the surface of the incline.- \( \vec{T} \): The tension in the cord acting towards the top of the incline.- \( \vec{F}_{g} \): The gravitational force acting vertically downward.- Angles and components are marked, showing \( 90° - \theta \) and the angle \( \theta \).#### Diagram (c)A coordinate system is depicted with axes \( x \) and \( y \), breaking down the gravitational force \( \vec{F}_{g} \) into components:- \( F_{g} \sin \theta \): The component of gravitational force parallel to the incline.- \( F_{g} \cos \theta \): The component of gravitational force perpendicular to the incline.This explanation and diagrams help in understanding how to calculate the tension in the cord, normal force, and subsequent acceleration when the cord is cut.

Answered: Image /qna-images/answer/e9f08229-bc94-44cf-ac13-b06b5f83f930.jpg

Refer to the figure. Let the mass of the block be 5.90 kg and the angle 8 be 29.0°. Find (a) the tension in the cord and (b) the normal force acting on the block. (c) If the cord is cut, find the magnitude of the block's acceleration. 0 90°-0- M Block 6 (b) Frictionless (a) F, sin 8 Fcos 6 Fsin 8 (c)

Refer to the figure. Let the mass of the block be 5.90 kg and the angle 8 be 29.0°. Find (a) the tension in the cord and (b) the normal force acting on the block. (c) If the cord is cut, find the magnitude of the block's acceleration. 0 90°-0- M Block 6 (b) Frictionless (a) F, sin 8 Fcos 6 Fsin 8 (c)

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Similar questions

Shown below is a 9.0-kg block being pushed by a horizontal force F of magnitude 350.0 N. The coefficient of kinetic friction between the two surfaces is 0.4. Find the acceleration of the block when is 27". F— a= 30.24 X 0 E% m
Write Newton's laws for a static system (1) EF, = mg sin 0 – µ̟n = 0 in component form. The gravity force has two components. (2) EF, = n - mg cos 0 = 0 Rearrange Equation (2) to get an n = mg cos e expression for the normal force n. Substitute the expression for n into EF, = mg sin 0 – µ̟mgcos 0 = 0 → tan 0 =µ, Equation (1) and solve for tan 0. Apply the inverse tangent function to tan 0 = 0.350 → 0 = tan 1 (0.350) = 19.3° get the answer. LEARN MORE REMARKS It's interesting that the final result depends only on the coefficient of static friction. Notice also how similar Equations (1) and (2) are to the equations developed in previous problems. Recognizing such patterns is key to solving problems successfully. QUESTION A larger static friction constant would result in a: (Select all that apply.) O larger component of normal force at the maximum angle. O larger component of gravitational force along the ramp at the maximum angle. smaller component of gravitational force along the ramp…
answer d please
A240 kg blockis inikiallyat rest on a horizontal surface. A horizontal force F of magnitude 6.01 Nand a vertical force 7 are then applied to the block see the figure). The coefficients of friction for the block and surface are s - 04 and -0.25. Determine the magnitude of the frictionalforce acting on the blockif the magnitude of P is (a)7.00 N and (b)10.0 N. (The upward pull is insufficient to move the block vertically) (a) Number Units (b) Number Units
A crate of mass 17.0 kg rests on a level surface. If the coefficient of kinetic friction between the crate and surface is 0.440, calculate the following. edi ume (a) Calculate the normal force. (Give the magnitude.) (b) Calculate the magnitude of the kinetic friction force when a horizontal applied force of 91.0 N moves the crate. (c) Calculate the normal force when the 91.0-N applied force is exerted at an angle of 32.5 above the horizontal. (Give the magnitude.) (d) Calculate the magnitude of the kinetic friction force when the 91.0-N applied force is exerted at an angle of 32.5 above the horizontal.
Asap
During strenuous exercise, it is possible to exert forces to the joints that are easily ten times greater than the weight being supported. What is the maximum force of friction (in N) under such conditions? (The frictional forces in joints are relatively small in all circumstances except when the joints deteriorate, such as from injury or arthritis. Increased frictional forces can cause further damage and pain.) she exert 67.0 kg of her mass on that knee?
(a) Calculate the tension (in N) in a vertical strand of spiderweb if a spider of mass 7.00 x 105 kg hangs motionless on it. (Enter a number.) N (b) Calculate the tension (in N) in a horizontal strand of spiderweb if the same spider sits motionless in the middle of it much like the tightrope walker in the figure. 5.0° 5,0° T. TR T I Ta w The strand sags at an angle of 12.0° below the horizontal. (Enter a number.) N Compare this with the tension in the vertical strand (find their ratio). (Enter a number.) (tension in horizontal strand)/(tension in vertical strand) =
A contestant in a winter games event pushes a 37.0 kg block of ice across a frozen lake as shown in the figure below. The coefficient of static friction is 0.1 and the coefficient of kinetic friction is 0.03. (For each answer, enter a number.) (a) Calculate the minimum force F (in N) he must exert to get the block moving.
A horizontal force is acting on a block moving on a rough horizontal surface. The force has the same magnitude ns the maximum fr rce of static frictica between the ' lock and the surfa e. If the coefficients of friction are Hs = %3D 0.75 and Hk = 0.50. Find the acceleration (in m/s?) of the block. 2.5 3.5 5.5 4.5 1.8
3C. A 100-N block on a rough 300-incline is acted upon by a force P as shown causing it to accelerate at 2 m/s< up the plane. The coefficient of kinetic friction is 0.30. (a) Draw the FBD of the block (b) Find the magnitude of P. 20° 30°
3F. A 100-N block on a rough 30°-incline is acted upon by a force P as shown causing it to accelerate at 2 m/s down the plane. The coefficient of kinetic friction is 0.30. (a) Draw the FBD of the block (b) Find the magnitude of P. P