**Physics Problem: Block on an Inclined Plane****Problem Statement:**Refer to the figure. Let the mass of the block be 5.90 kg and the angle θ be 29.0°. Find (a) the tension in the cord and (b) the normal force acting on the block. (c) If the cord is cut, find the magnitude of the block's acceleration.**Diagrams:**- **Figure (a):** - A block of mass \( m \) is placed on an inclined plane with an angle of θ to the horizontal. - The incline is labeled as frictionless. - A cord is attached to the block, preventing it from sliding down the plane.- **Figure (b):** (Free Body Diagram - Block on Incline) - A coordinate system is established, with the x-axis along the incline and the y-axis perpendicular to it. - Forces acting on the block: - \( \vec{F}_N \) (Normal Force): Perpendicular to the inclined surface. - \( \vec{T} \) (Tension): Up the incline. - \( \vec{F}_g \) (Gravitational Force): Acting vertically downward. - Angle \( 90° - θ \) is marked between the vertical and the normal force.- **Figure (c):** (Resolution of Forces) - Gravitational force \( \vec{F}_g \) is resolved into components: - \( F_g \sin θ \): Component parallel to the incline. - \( F_g \cos θ \): Component perpendicular to the incline. - The block's weight acts downwards and is decomposed into these components in the x and y directions as defined by the inclined plane's coordinate system.This setup allows you to apply Newton's laws to solve for tension, normal force, and acceleration.

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Refer to the figure. Let the mass of the block be 5.90 kg and the angle 8 be 29.0°. Find (a) the tension in the cord and (b) the normal force acting on the block. (c) If the cord is cut, find the magnitude of the block's acceleration. 0 m Frictionless 3

Refer to the figure. Let the mass of the block be 5.90 kg and the angle 8 be 29.0°. Find (a) the tension in the cord and (b) the normal force acting on the block. (c) If the cord is cut, find the magnitude of the block's acceleration. 0 m Frictionless 3

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Question

**Physics Problem: Block on an Inclined Plane**

**Problem Statement:**
Refer to the figure. Let the mass of the block be 5.90 kg and the angle θ be 29.0°. Find (a) the tension in the cord and (b) the normal force acting on the block. (c) If the cord is cut, find the magnitude of the block's acceleration.

**Diagrams:**

- **Figure (a):**
- A block of mass \( m \) is placed on an inclined plane with an angle of θ to the horizontal.
- The incline is labeled as frictionless.
- A cord is attached to the block, preventing it from sliding down the plane.

- **Figure (b):** (Free Body Diagram - Block on Incline)
- A coordinate system is established, with the x-axis along the incline and the y-axis perpendicular to it.
- Forces acting on the block:
- \( \vec{F}_N \) (Normal Force): Perpendicular to the inclined surface.
- \( \vec{T} \) (Tension): Up the incline.
- \( \vec{F}_g \) (Gravitational Force): Acting vertically downward.
- Angle \( 90° - θ \) is marked between the vertical and the normal force.

- **Figure (c):** (Resolution of Forces)
- Gravitational force \( \vec{F}_g \) is resolved into components:
- \( F_g \sin θ \): Component parallel to the incline.
- \( F_g \cos θ \): Component perpendicular to the incline.
- The block's weight acts downwards and is decomposed into these components in the x and y directions as defined by the inclined plane's coordinate system.

This setup allows you to apply Newton's laws to solve for tension, normal force, and acceleration.

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