Refer to Figure 3.7 Segments 1 and 2. What would be the approximate slab thickness if the mean modulus of rupture S’c is increased to 750 psi and all other conditions in the example shown in Figure  3.7 remain the same? a. 5.0 inches b. 7.0 inches c. 9.0 inches d. 11.0 inches e. 13.0 inches

Structural Analysis
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Chapter2: Loads On Structures
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16. Refer to Figure 3.7 Segments 1 and 2. What would be the approximate slab thickness if the mean
modulus of rupture S’c is increased to 750 psi and all other conditions in the example shown in Figure 
3.7 remain the same?
a. 5.0 inches
b. 7.0 inches
c. 9.0 inches
d. 11.0 inches
e. 13.0 inches

NOMOGRAFH SOLVES:
109101825+ 7.35*10% (D+1) - 0.06 +
Concrete Elastic Modulus, Ę₂ (10p)
800 500
CO
Effective Modulus of Subgrade
Reaction, k (pci)
10910
APSI
4.5-1.5
1+
1.624*107
(D+1)
12:00
7100
1000
100
700
+ (4.22-0.32p)*10910
600
500
Mean Concrete Modulus of Rupture, S'e (psi)
TL
Sc Ca
5 * ₁ [00.75 -1.132]
215.63*
28 29 3
TMMMMMMMMMM
40-
220
· [20.75.
Load Transfer
Coefficient, J
Example
k = 72 pci
Ec ¹5x10
s'c =
J = 3.2
Cd = 1.0
18.42
(EX) 0.25
TL
pul
= 650 psl
Drainage Coefficient, Cd
0.5
0.7
10-
20
30
40
50
60
70
80
90
100-
Match Line
50
0.29
R = 95% (Z₁,-1,645)
APSI = 4.2-2.5 = 1.7
Wa 5J x 106 (18 hip ESAL)
Solution: D=10.0 inches (nearest
holt-inch, from segment 2)
Figure 3.7. Design Chart for Rigid Pavement Based on Using Mean Values for Each Input Variable (Segment 1)
Transcribed Image Text:NOMOGRAFH SOLVES: 109101825+ 7.35*10% (D+1) - 0.06 + Concrete Elastic Modulus, Ę₂ (10p) 800 500 CO Effective Modulus of Subgrade Reaction, k (pci) 10910 APSI 4.5-1.5 1+ 1.624*107 (D+1) 12:00 7100 1000 100 700 + (4.22-0.32p)*10910 600 500 Mean Concrete Modulus of Rupture, S'e (psi) TL Sc Ca 5 * ₁ [00.75 -1.132] 215.63* 28 29 3 TMMMMMMMMMM 40- 220 · [20.75. Load Transfer Coefficient, J Example k = 72 pci Ec ¹5x10 s'c = J = 3.2 Cd = 1.0 18.42 (EX) 0.25 TL pul = 650 psl Drainage Coefficient, Cd 0.5 0.7 10- 20 30 40 50 60 70 80 90 100- Match Line 50 0.29 R = 95% (Z₁,-1,645) APSI = 4.2-2.5 = 1.7 Wa 5J x 106 (18 hip ESAL) Solution: D=10.0 inches (nearest holt-inch, from segment 2) Figure 3.7. Design Chart for Rigid Pavement Based on Using Mean Values for Each Input Variable (Segment 1)
10-
30
o
6
70
9
Match Line
300-
Design Serviceability Loss, APSI
TH
ndoo
Design Slob Thickness, D (inches)
NOTE Application of reliability
HALSE
1000 500
In this charl requires
the use of mean values
for all the input variables.
14 13 12 11 10
HA
Estimated Total 18-kip Equivalent Single Axle
Load (ESAL) Applications, W (millions)
10 15
100
50
999
9
10
8
Overall Standard Deviation, S
لليث
90
6
UM
05
5
80 70 60 50
Reliability, R (%)
Figure 3.7. Continued-Design Chart for Rigid Pavements Based on Using Mean Values for
Each Input Variable (Segment 2)
9
Transcribed Image Text:10- 30 o 6 70 9 Match Line 300- Design Serviceability Loss, APSI TH ndoo Design Slob Thickness, D (inches) NOTE Application of reliability HALSE 1000 500 In this charl requires the use of mean values for all the input variables. 14 13 12 11 10 HA Estimated Total 18-kip Equivalent Single Axle Load (ESAL) Applications, W (millions) 10 15 100 50 999 9 10 8 Overall Standard Deviation, S لليث 90 6 UM 05 5 80 70 60 50 Reliability, R (%) Figure 3.7. Continued-Design Chart for Rigid Pavements Based on Using Mean Values for Each Input Variable (Segment 2) 9
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