Refer image to questions - What are the degrees of freedom? (choose from below) 46 45 43 92 - What is the correct decision for this test?(choose from below) Since p-value > 0.05, do not reject H0 Since p-value < 0.05, reject H0 Since p-value > 0.05, reject H0 Since p-value < 0.05, do not reject H0 - An appropriate conclusion for this test is (choose from below) -The first pulse rates of students who did not run are significantly higher than the first pulse rates of students who did run -The first pulse rates of students who did not run are the same as the second pulse rates of students who did not run -The first pulse rates of students who did not run could be the same as the second pulse rates of students who did not run -The first pulse rates of students who did not run are significantly lower than the second pulse rates of students who did not run
Refer image to questions - What are the degrees of freedom? (choose from below) 46 45 43 92 - What is the correct decision for this test?(choose from below) Since p-value > 0.05, do not reject H0 Since p-value < 0.05, reject H0 Since p-value > 0.05, reject H0 Since p-value < 0.05, do not reject H0 - An appropriate conclusion for this test is (choose from below) -The first pulse rates of students who did not run are significantly higher than the first pulse rates of students who did run -The first pulse rates of students who did not run are the same as the second pulse rates of students who did not run -The first pulse rates of students who did not run could be the same as the second pulse rates of students who did not run -The first pulse rates of students who did not run are significantly lower than the second pulse rates of students who did not run
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
Refer image to questions
- What are the degrees of freedom? (choose from below)
46 | 45 | 43 | 92 |
- What is the correct decision for this test?(choose from below)
Since p-value > 0.05, do not reject H0
Since p-value < 0.05, reject H0
Since p-value > 0.05, reject H0
Since p-value < 0.05, do not reject H0
- An appropriate conclusion for this test is (choose from below)
-The first pulse rates of students who did not run are significantly higher than the first pulse rates of students who did run
-The first pulse rates of students who did not run are the same as the second pulse rates of students who did not run
-The first pulse rates of students who did not run could be the same as the second pulse rates of students who did not run
-The first pulse rates of students who did not run are significantly lower than the second pulse rates of students who did not run

Transcribed Image Text:pulseB_NR<-subset (pulseB, Ran =="No")
t.test (pulseB_NR$Pulsel, pulseB_NR$Pulse2, paired=T)
Paired t-test
data: pulseB_NR$Pulsel and pulseB_NR$Pulse2
t = 0.16638, df = 46, p-value = 0.8686
alternative hypothesis: true difference in means is not equal to 0
95 percent confidence interval:
-0. 9444994 1.1147122
sample estimates:
mean of the differences
Difference in Pulse Rates of NonRunners
0.08510638
-10
-5
diff_Notran
Frequency
4 8 12
Expert Solution

Step 1
From given Image, we get
Hypothesis :
Null hypothesis (H0) : True difference in means is equal to 0
Alternative hypothesis (H1) : True difference in means is not equal to 0
Test statistic : t = 0.16638
Degrees of freedom (df) = 46
P-value = 0.8686
Step by step
Solved in 2 steps
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