What are the degrees of freedom? (choose from below) 1 31 30 27 26 - What is the correct decision for this test? (choose from below) Since p-value > 0.05, do not reject H0 Since p-value < 0.05, reject H0 Since p-value > 0.05, reject H0 Since p-value < 0.05, do not reject H0 -. An appropriate conclusion for this test is(choose from below) -Significantly more than 50% of females are moderately active -Significantly less than 50% of females are moderately active
What are the degrees of freedom? (choose from below) 1 31 30 27 26 - What is the correct decision for this test? (choose from below) Since p-value > 0.05, do not reject H0 Since p-value < 0.05, reject H0 Since p-value > 0.05, reject H0 Since p-value < 0.05, do not reject H0 -. An appropriate conclusion for this test is(choose from below) -Significantly more than 50% of females are moderately active -Significantly less than 50% of females are moderately active
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
Refer image to questions
- What are the degrees of freedom? (choose from below)
| 1 | 31 | 30 | 27 | 26 |
- What is the correct decision for this test? (choose from below)
Since p-value > 0.05, do not reject H0
Since p-value < 0.05, reject H0
Since p-value > 0.05, reject H0
Since p-value < 0.05, do not reject H0
-. An appropriate conclusion for this test is(choose from below)
-Significantly more than 50% of females are moderately active
-Significantly less than 50% of females are moderately active
-There is not enough evidence to reject the claim that 50% of females are moderately active
-None of the these
Transcribed Image Text:Activity.table<-table(pulseB_f$Activity)
Activity.table
A lot Moderate
slight
4
20
7
prop. test (20,27,0. 5, correct=TRUE)
Activity Levels of Female Students
1-sample proportions test with continuity correction
data: 20 out of 27, null probability 0. 5
x-squared
alternative hypothesis: true p is not equal to 0.5
95 percent confidence interval:
0. 5340628 0.8812706
sample estimates:
5. 3333, df = 1, p-value = 0.02092
%3D
p.
0.7407407
A Lot Moderate Slight
Expert Solution
Step 1
Given :
From the given output :
Test statistic is 5.3333
Hypothesis test :
The null and alternative hypothesis is
Ho : true p is equal to 0.50
Ha : true p is not equal to 0.50
Step by step
Solved in 4 steps
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