Refer back to the data in Exercise 4, in which y = ammonium concentration (mg/L) and x = transpiration (ml/h). Summary quantities include n = 13, Ex; = 303.7,Eyi = 52.8, Sxx 1585.230769, S,xy = -341.959231, and Syy = 77.270769. %3D
Correlation
Correlation defines a relationship between two independent variables. It tells the degree to which variables move in relation to each other. When two sets of data are related to each other, there is a correlation between them.
Linear Correlation
A correlation is used to determine the relationships between numerical and categorical variables. In other words, it is an indicator of how things are connected to one another. The correlation analysis is the study of how variables are related.
Regression Analysis
Regression analysis is a statistical method in which it estimates the relationship between a dependent variable and one or more independent variable. In simple terms dependent variable is called as outcome variable and independent variable is called as predictors. Regression analysis is one of the methods to find the trends in data. The independent variable used in Regression analysis is named Predictor variable. It offers data of an associated dependent variable regarding a particular outcome.
For the following, use the data from the (#12, Section 12.2) (please see the attached file.
- a) Calculate the value of the sample
correlation coefficient . Based on this value, how would you describe the nature of the relationship between the two variables? - b) If the units of y were changed to g/L, would your answer to part a) change?
- c) For the regression model in #12a, what proportion of the observed variation in ammonium concentration can be attributed to the approximate linear relationship between transpiration and ammonium concentration?
![Section 12.2
#12ab
Refer back to the data in Exercise 4, in which y = ammonium concentration (mg/L) and x
transpiration (ml/h). Summary quantities include n= 13, Ex; = 303.7, Eyi = 52.8, Sxx
1585.230769, Sxy
%3D
%3D
%3D
%D
= -341.959231, and S = 77.270769.
yy
a. Obtain the equation of the estimated regression line and use it to calculate a point prediction of
ammonium concentration for a future observation made when ammonium concentration is 25
ml/h.
b. What happens if the estimated regression line is used to calculate a point estimate of true
average concentration when transpiration is 45 ml/h? Why does it not make sense to calculate
this point estimate?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9e2597a6-f559-4086-95a9-d32d556d6ca5%2Feaa258f4-5c91-4eeb-9168-3d20dd97f89e%2Fubsof2_processed.jpeg&w=3840&q=75)
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