Refer attached figure of an axial reluctance force actuator on Image 1. While ignoring core reluctances, find the reluctance force, F, if x = 0.004 m and I = 5 A using the atached force expression on attached image 2.
Refer attached figure of an axial reluctance force actuator on Image 1. While ignoring core reluctances, find the reluctance force, F, if x = 0.004 m and I = 5 A using the atached force expression on attached image 2.
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Refer attached figure of an axial reluctance force actuator on Image 1. While ignoring core reluctances, find the reluctance force, F, if x = 0.004 m and I = 5 A using the atached force expression on attached image 2.

Transcribed Image Text:1) Axial Reluctance Actuator
An axial reluctance force actuator is shown in Figure 1. The actuator is excited by a coil of N=||
500 turns and the positive direction of current flow is indicated by the arrow. The core has a
constant cross sectional area with width, w = 0.04 m, and depth, d= 0.04 m. For your initial
analysis ignore core reluctances but do not neglect fringing.
w = 0.04 m
w = 0.04 m
N = 500 turns
3w
w = 0.04 m
w = 0.04 m
w = 0.04 m
w = 0.04 m
W =
w = 0.04 m
3w
田

Transcribed Image Text:dR
F= -
dx
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