Red LED Si IR Vo +12 Vo 1.8 V ID 680 N Figure 3
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![Red LED
Si
IR
oVo
+12 Vo
1.8 V
ID
680 N
Figure 3](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Feed60eaa-d8b9-4d5c-8dd2-8a4f24e9b7ea%2F700225e2-162b-4084-a9cc-1c07325c5942%2Fc99pj88_processed.jpeg&w=3840&q=75)
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- As the capacitor in an RC circuit charged, what is the current as a function of time?Explain physically.A circuit containing five resistors connected to a battery with a 12 V emf is shown below. What is the potential difference across the 5 ohm resistor? What is the current flowing through the 12 ohm resistor?Describe two ways in which you can test Ohm's Law.
- How does the resistance of a wire depend on its radius? Explain your answer.+8 m → 4) Find the resistance and capacitance of the following truncated pyramidal material along its axis (assume current flows through its axis, resistivity is po = const., dielectric constant is ɛ, = const). 3 m 4 m HX N 3) Consider a cube whose center is at the origin, and all edges of the cube are 4 cm. A battery (DC voltage) with voltage of Vo is connected to bottom and top faces (sides) of cube as shown in left figure. a) If the volume current density in cube is given as; J=100 V₁ (x² + y²)â. A/m² then find the (DC) resistance of the structure. Hint: You can get the result without considering below part (part b). O= b) By assuming that electric field intensity is zero outside the cube (although practically there is nonzero electric field outside the cube, assume that this electric field is very small), if the conductivity of the material of the cube is given as; x² 1+ Z 0.02 10-2 S m then find and express free charge densities (where they exist) in terms of battery voltage Vo. Take cube material's relative permittivity (dielectric constant) as &r = 1.