Please help **Transcription for Educational Website:**---**Instruction:**Predict the major organic product for the reaction shown below. Use wedge and dash bonds to indicate relative stereochemistry where appropriate. Ignore inorganic byproducts.**Chemical Reaction:**A benzene ring with a substituent is shown, featuring a methyl group and a new bond extending from the ring.**Reaction Conditions:**- **Reagents:** OsO₄ (catalytic), NMO**Diagram:**Below the reaction arrow, there is a dashed box labeled "Select to Draw," indicating where the student should draw the reaction product.---**Explanation of Diagram:**The diagram illustrates the setup for a chemical reaction involving a benzene ring with a single substituent (likely an alkene group indicated by wedge and dash bonds for stereochemistry). The reaction conditions involve using osmium tetroxide (OsO₄) in catalytic amounts with N-Methylmorpholine N-oxide (NMO) as a co-oxidant. The student is expected to predict the outcome using the given guidelines and tools.

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Answered: reaction shown below. Use wedge and…

reaction shown below. Use wedge and dash bonds to indicate relative stereochemistry where appropriate. Ignore inorganic byproducts. Please selec Os04 (catalytic) NMO Select to Draw

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Should be 3 answers in total. Will thumbs up! Next the student conducts two different runs: In RUN 1, 10.0 mL of 5.00 M NAOH is combined with 10.0 mL of 0.010 M CO and 80.0 mL of wate In RUN 2, 20.0 mL of 5.00 M NAOH is combined with 10.0 mL of 0.010 M CO and 70.0 mL of wate The following plots were obtained for each of the runs: [crystal orange] vs time (RUN 1) In[crystal orange] vs time (RUN 1) 0.0012 0.001 -2 y--0.4463x- 7.3334 y =-0.0002x + 0.0007 R- 0.6565 R = 0.893 0.0008 4 0.0006 -6 0.0004 -8 0.0002 0.0002 -12 time (hr) time (hr) 1/[crystal orange] vs time (RUN 1) 1/[crystal orange] vs time (RUN 2) 12000 25000 10000 20000 8000 15000 6000 y = 2000x + 1000 R =1 10000 y 4000x + 1000 R =1 4000 2000 5000 time (hr) time (hr) Figure 4. Kinetic traces for the reaction between crystal orange and sodium hydroxide. What is the order with respect to CO? | Select ] What is the order with respect to NaOH? | Select ] What is the value of the averaged rate constant for the reaction above? Give…
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