The image is an interactive educational component that helps calculate the molarity of an aqueous solution. The problem statement is:"What is the molarity of an aqueous solution that contains 0.072 g C₂H₆O₂ per gram of solution. The density of the solution is 1.04 g/mL."### Components:1. **Starting Amount Section:** - A labeled box titled "STARTING AMOUNT;" currently this area is empty for input.2. **Equation Setup:** - A multiplication and division setup with empty boxes for input. It's set up as: - Starting Amount \( \times \left(\frac{\text{Numerator}}{\text{Denominator}}\right) \)3. **Control Panel:** - **Add Factor:** Allows input of numbers or expressions, e.g., \( \times ( \quad ) \) - **Inputs Available:** - Numbers: 62.08, 1.04, 0.072, 1, 1.21 × 10⁻³, 0.001, 1000, 1.12 - Constants: 6.022 × 10²³, 4650, 1.21 - **Units and Labels:** - g solution/mL, M C₂H₆O₂, g solution, mL solution - mol C₂H₆O₂, g C₂H₆O₂/mol, g C₂H₆O₂ - L solution, g C₂H₆O₂/g solution4. **Answer and Reset:** - **Answer:** An empty box labeled "=" for the result. - **Reset Button:** A circular arrow icon for clearing the inputs.### Diagram Explanation:- The setup guides users in calculating molarity by using given inputs like the mass of solute per gram of solution and the density.- It offers a structured method to plug in different conversion factors step-by-step.This interactive tool aids learners in understanding the relationship between mass, volume, and concentration in chemistry.

The number of moles for a given chemical species refers to the ratio of mass of the species to that of its molar mass. The formula is shown below: The molarity or the concentration can be defined as the ratio of number of moles of solute which are present per liter of the given solution. The SI units of molarity are moles/L. The mathematical formula as follows: The mass of C2H6O2 is given to be 0.072 g. The density of the solution is given to be 1.04 g/mL. It has also been given that 0.072 g of C2H6O2 is present per gram of the solution. The Volume of 1g of solution can be calculated as follows: This means that in 0.9615 mL of solution, 0.072 g of C2H6O2 is present. The mass of C2H6O2 which is present in 1 mL of solution can be calculated as follows: The moles of C2H6O2 which is present in 1 mL of solution can be calculated as follows: Therefore, 0.00121 mol of C2H6O2 is present in 1 mL of solution. The number of moles of solute which are present in one liter of solution is termed as molarity. Hence, the molarity of the solution can be calculated as follows: Answer: The molarity of the given solution is found to be 1.21 moles/L.