Reaction: P4010(s) + 6 H20(1) → 4 H3PO4(1) P4010(s) AH•F (kJ mol-1) = -2984.0 S° (J K-1 mol-1) = 228.86 Calculate the entropy change for the system. Show labelled work! b. Calculate the entropy change for the surroundings (hint: find AH first). Show labelled work! а. Calculate the total entropy change, ASuniverse, for this reaction (assuming С. T=25 °C)

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Chapter1: Chemical Foundations
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Reaction:
P4010(s) + 6 H20(1)
4
H3PO4(1)
P4010(s)
AH•F (kJ mol-1) = -2984.0
%3D
S° (J K-1 mol-1) = 228.86
Calculate the entropy change for the
system. Show labelled work!
b. Calculate the entropy change for the
surroundings (hint: find AH first). Show
labelled work!
а.
Calculate the total entropy change,
ASuniverse, for this reaction (assuming
С.
T=25 °C)
d. From a thermodynamics perspective
then, based on your value for
ASuniverse are reactants more likely to
proceed to products or remain as
reactants?
Transcribed Image Text:Reaction: P4010(s) + 6 H20(1) 4 H3PO4(1) P4010(s) AH•F (kJ mol-1) = -2984.0 %3D S° (J K-1 mol-1) = 228.86 Calculate the entropy change for the system. Show labelled work! b. Calculate the entropy change for the surroundings (hint: find AH first). Show labelled work! а. Calculate the total entropy change, ASuniverse, for this reaction (assuming С. T=25 °C) d. From a thermodynamics perspective then, based on your value for ASuniverse are reactants more likely to proceed to products or remain as reactants?
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