Readion Cone, Nay S0, Cine HCI|Ab. 1 | RabeI1.308584065.56796607Cone, Nagd, 03ATme (5)0.10 M·30M 04563164 |0.028 F09 13,15 M 12267196|0.0187091330M |1.5360817 0.300349O.10 M30.050 M5. 1143167140.025 M0:30M1.36866111,3583808741.0075683. What is the overall order of the reaction? Write the complete rate law for this reaction.

Answered: Reaction Conc, Nagd 0, Cone. HCI Als. I…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Readion Cone, Nay S0, Cine HCI|Ab. 1 | Rabe
I1.3085840
65.56796607
Cone, Nagd, 03
ATme (5)
0.10 M
·30M 04563164 |0.028 F09 13
,15 M 12267196|0.01870913
30M |1.5360817 0.300349
O.10 M
3
0.050 M
5. 11431671
4
0.025 M
0:30M
1.3686611
1,358380874
1.007568
3. What is the overall order of the reaction? Write the complete rate law for this reaction.

Expert Solution

Step 1

$R a t e = K {[A]}^{m} {[B]}^{n} C o n s i d e r i n g R e a c t i o n 1 a n d r e a c t i o n 2 \frac{r a t e_{1}}{r a t e_{2}} = \frac{K {(0.10)}^{m} {(0.30)}^{n}}{K {(0.10)}^{m} {(0.15)}^{n}} \frac{11.3085840}{65.56796607} = 2^{n} c a l c u l a t i n g t h e v a l u e o f n, t a k i n g \ln o n b o t h t h e s i d e s \ln (0.17) = n \ln 2 d i v i d i n d b o t h s i d e s b y \ln 2 n = \frac{\ln (0.17)}{\ln (2)} n = - 2.5 N o t e : O r d e r c a n n e v e r b e n e g a t i v e b u t o r d e r w . r . t t o s p e c i f i c r e a c \tan t c a n b e n e g a t i v e$

$C o n s i d e r i n g r e a c t i o n 3 a n d 4 \frac{r a t e_{3}}{r a t e_{4}} = \frac{K {[A]}^{m} {[B]}^{n}}{K {[A]}^{m} {[B]}^{n}} \frac{5.11431671}{1.358380874} = \frac{{[0.050]}^{m}}{{[0.025]}^{m}} c a l c u l a t i n g t h e v a l u e o f m I n s i m i l a r w a y f i n d t h e v a l u e o f m a s c a l c u l a t e d f o r n$

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