Calculate the K₂ from the following data.H₂S1.000 M0.9923 M0.0077 Mstart:equil:K₂ =Ka+2 H₂OThe amount of H₂S that was converted into product isThe stoichiometry tells us that 1 mol H₂S will give usThus,M H₂S will giveu. H₂O(lig)aa. 0.9923hh. 1.84 x 10-65][2 H₂O+00.0154 Mb. hydrochloric c. phosphorich. CaCO3(s) i. OH-1j. H30+10. H₂PO4-¹ p. CO3²q. HCO3-¹v. H₂CO3 W. PO4³cc. 3bb. 0.0077ii. 0.01250+the concentration of [H3O+¹] is squared because its coefficient is 2a. aceticd. Al+3k. SO4²g. HF (aq)n. HPO ²r. H₂SS-²00.0077 Mx. HCzH3O2dd. 21²jj. 0.22100 kk. 0.05656MS-² ande. CO₂Mmol of S-² andy. C₂H30₂-1ee. 1 ff. 0.01541. Mg+2S. HS-1f. CaF2(aq)m. CI-1t. S-2z. 1 x 10-14gg. 3.95 x 10-3mol of H30+1M H30+1

Acid dissociation constant Ka for a reaction is defined as the product of the molar concentrations…

Calculate the K, from the following data. start: equil: Ka Ka H₂S 1.000 M 0.9923 M 0.0077 M + g. HF(aq) n. HPO ² u. H₂O(lig) aa. 0.9923 2 H₂O The amount of H₂S that was converted into product is The stoichiometry tells us that 1 mol H₂S will give us Thus, M H₂S will give ][ S X 2 H₂O+ 0 0.0154 M c. phosphoric the concentration of [H3O+¹] is squared because its coefficient is 2 a. acetic b. hydrochloric d. Al+3 h. CaCO3(s) i. OH-¹ k. SO4² o. H₂PO4-¹ P. CO32 r. H₂S v. H₂CO3 W. PO4³ bb. 0.0077 cc. 3 j. H30+1 q. HCO3-¹ + x. HC2H3O2 dd. 2 S-² 0 0.0077 M 1² e. CO₂ MS-2 and M mol of S-² and 1. Mg+2 s. HS-1 y. C₂H30₂-1 ee. 1 ff. 0.0154 f. CaF2(aq) m. CI-1 t. 5-² Z. 1 x 10-14 gg. 3.95 x 10-3 mol of H30+1 M H30+1

Calculate the K, from the following data. start: equil: Ka Ka H₂S 1.000 M 0.9923 M 0.0077 M + g. HF(aq) n. HPO ² u. H₂O(lig) aa. 0.9923 2 H₂O The amount of H₂S that was converted into product is The stoichiometry tells us that 1 mol H₂S will give us Thus, M H₂S will give ][ S X 2 H₂O+ 0 0.0154 M c. phosphoric the concentration of [H3O+¹] is squared because its coefficient is 2 a. acetic b. hydrochloric d. Al+3 h. CaCO3(s) i. OH-¹ k. SO4² o. H₂PO4-¹ P. CO32 r. H₂S v. H₂CO3 W. PO4³ bb. 0.0077 cc. 3 j. H30+1 q. HCO3-¹ + x. HC2H3O2 dd. 2 S-² 0 0.0077 M 1² e. CO₂ MS-2 and M mol of S-² and 1. Mg+2 s. HS-1 y. C₂H30₂-1 ee. 1 ff. 0.0154 f. CaF2(aq) m. CI-1 t. 5-² Z. 1 x 10-14 gg. 3.95 x 10-3 mol of H30+1 M H30+1

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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