a. HF(aq) + Cl0¯ (aq) 2 F¯(aq) + HCIO(aq) O The equilibrium lies predominantly to the right. The equilibrium lies predominantly to the left. (Ni(H, O), OH * (aq) + HPO,² (aq) = [Ni(H,O).]* (aq) + PO,* (aq) O The equilibrium lies predominantly to the right. O The equilibrium lies predominantly to the left. c. NH, + (aq) + H,PO,¯(aq) 2 NH3 (aq) + H3PO4(aq) O The equilibrium lies predominantly to the right. O The equilibrium lies predominantly to the left.
a. HF(aq) + Cl0¯ (aq) 2 F¯(aq) + HCIO(aq) O The equilibrium lies predominantly to the right. The equilibrium lies predominantly to the left. (Ni(H, O), OH * (aq) + HPO,² (aq) = [Ni(H,O).]* (aq) + PO,* (aq) O The equilibrium lies predominantly to the right. O The equilibrium lies predominantly to the left. c. NH, + (aq) + H,PO,¯(aq) 2 NH3 (aq) + H3PO4(aq) O The equilibrium lies predominantly to the right. O The equilibrium lies predominantly to the left.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
![For the following reactions, predict whether the equilibrium lies predominantly to the left or to the right.
Къ(NH,) - 1.8х 10-5
Ionization Constants for Aqueous Weak Acids at 25 °C
Acid
Formula and Ionization Equation
K.
Acetic
CH,CO,H= H + CH3CO,
1.8 x 10-
K = 5.8 x 10-
K2 = 1.1 x 10-
K = 3.2 x 10-12
H3 AsO, 2H* + Hz AsO,
H2 AsO, H* + HASO,
HASO, =H+ + AsO,
H3 AsO, 2 H* +H2ASO3
H2 AsO, H+ + HASO,
C, H; CO;H= H* + C,H; CO;
H;BOs 2H* + H2BO3
H, BO, 2H* + HBO,
HBO; 2H* + BO,
H2CO, 2 H* + HCO3
HCO, H + Co,
Arsenic
K1 = 6.0 x 10-10
K, = 3.0 x 10-14
Arsenous
Benzoic
6.3 x 10-5
K = 7.3 x 10-10
K2 = 1.8 x 10-
K = 1.6 x 10-14
Boric
K1 = 4.2 x 10-7
K, = 4.8 x 10-11
Carbonic
H3C,H;O, 2 H+ + H2C,H,O;
H;C,H, O; H' + HC,H, O;2
HC,Hs 0, 2H* + C, H; O,
K = 7.4 x 10
K = 1.7 x 10-5
K, = 4.0 x 10-7
Citric
Cyanic
HOCN 2 H* +OCN
HCO,H2H + HCO,
3.5 x 104
Formic
1.8 x 104
Hydrazoic
Hydrocyanic
HN3 2H* + N3
1.9 x 10-5
HCN H* + CN
4.0 x 10-10
Hydrofluoric
Hydrogen
peroxide
HF 2H* + F
7.2 x 104
H2O, 2 H* + Ho,
2.4 x 10-12
H2S H* + HS
HS 2H* + s
K1 =1 x 10-7
K =1 x 10-19
Hydrosulfuric
HOBR2H* + OBr
|Нуpobromous
|Нурochlorous
2.5 x 10-
HOCI 2H* + OCI
2.5 x 10
Nitrous
HNO, PH* + NO:
H,C,0, 2H + HC20,
HC20, H* + C20,
4.5 x 104
K1 = 5.9 x 10-2
K = 6.4 x 10
Oxalic
Phenol
C,H;OH =H* + C,H;O
1.3 x 10-10
H3PO, 2 Ht + H2PO,
H,PO, H+ + HPO,
HPO, H* + PO,
K = 7.5 x 10-
K, = 6.2 x 10-8
К, 3.6 х 10-13
Phosphoric
H3PO3 H* + H2PO3
H,PO,- 2H+ + HPO,
H2 SeO, H* + HSeO,
HSEO, 2H + SeO,
H, SeO H* + HSeO;
HSEO, H + SeO,
H2SO, H* + HSO,-
HSO,- 2H+ + so,
Phosphorous
K1 = 1.6 x 10-
K2 = 7.0 x 10-7
K1 = very large
K = 1.2 x 10-2
Selenic
x 10
K1 = 2.7 x
|Ку 2.5 х 10-7
K = very large
K = 1.2 x 10-2
Selenous
Sulfuric
H2SO, 2H* + HSO;
2-
HSO, H + SO,
|К - 1.2 х 10-2
K, = 6.2 x 10
Sulfurous
H, TeO; =H+ + HT@O3
HTEO, 2H + TeO,
K1 = 2 x 10
K2 =1 x 10-*
Tellurous](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6b655049-7826-439f-8581-abd316b9e58a%2F10c82c08-0942-4029-a9cc-d0468ba35ad4%2F4p0miu_processed.png&w=3840&q=75)
Transcribed Image Text:For the following reactions, predict whether the equilibrium lies predominantly to the left or to the right.
Къ(NH,) - 1.8х 10-5
Ionization Constants for Aqueous Weak Acids at 25 °C
Acid
Formula and Ionization Equation
K.
Acetic
CH,CO,H= H + CH3CO,
1.8 x 10-
K = 5.8 x 10-
K2 = 1.1 x 10-
K = 3.2 x 10-12
H3 AsO, 2H* + Hz AsO,
H2 AsO, H* + HASO,
HASO, =H+ + AsO,
H3 AsO, 2 H* +H2ASO3
H2 AsO, H+ + HASO,
C, H; CO;H= H* + C,H; CO;
H;BOs 2H* + H2BO3
H, BO, 2H* + HBO,
HBO; 2H* + BO,
H2CO, 2 H* + HCO3
HCO, H + Co,
Arsenic
K1 = 6.0 x 10-10
K, = 3.0 x 10-14
Arsenous
Benzoic
6.3 x 10-5
K = 7.3 x 10-10
K2 = 1.8 x 10-
K = 1.6 x 10-14
Boric
K1 = 4.2 x 10-7
K, = 4.8 x 10-11
Carbonic
H3C,H;O, 2 H+ + H2C,H,O;
H;C,H, O; H' + HC,H, O;2
HC,Hs 0, 2H* + C, H; O,
K = 7.4 x 10
K = 1.7 x 10-5
K, = 4.0 x 10-7
Citric
Cyanic
HOCN 2 H* +OCN
HCO,H2H + HCO,
3.5 x 104
Formic
1.8 x 104
Hydrazoic
Hydrocyanic
HN3 2H* + N3
1.9 x 10-5
HCN H* + CN
4.0 x 10-10
Hydrofluoric
Hydrogen
peroxide
HF 2H* + F
7.2 x 104
H2O, 2 H* + Ho,
2.4 x 10-12
H2S H* + HS
HS 2H* + s
K1 =1 x 10-7
K =1 x 10-19
Hydrosulfuric
HOBR2H* + OBr
|Нуpobromous
|Нурochlorous
2.5 x 10-
HOCI 2H* + OCI
2.5 x 10
Nitrous
HNO, PH* + NO:
H,C,0, 2H + HC20,
HC20, H* + C20,
4.5 x 104
K1 = 5.9 x 10-2
K = 6.4 x 10
Oxalic
Phenol
C,H;OH =H* + C,H;O
1.3 x 10-10
H3PO, 2 Ht + H2PO,
H,PO, H+ + HPO,
HPO, H* + PO,
K = 7.5 x 10-
K, = 6.2 x 10-8
К, 3.6 х 10-13
Phosphoric
H3PO3 H* + H2PO3
H,PO,- 2H+ + HPO,
H2 SeO, H* + HSeO,
HSEO, 2H + SeO,
H, SeO H* + HSeO;
HSEO, H + SeO,
H2SO, H* + HSO,-
HSO,- 2H+ + so,
Phosphorous
K1 = 1.6 x 10-
K2 = 7.0 x 10-7
K1 = very large
K = 1.2 x 10-2
Selenic
x 10
K1 = 2.7 x
|Ку 2.5 х 10-7
K = very large
K = 1.2 x 10-2
Selenous
Sulfuric
H2SO, 2H* + HSO;
2-
HSO, H + SO,
|К - 1.2 х 10-2
K, = 6.2 x 10
Sulfurous
H, TeO; =H+ + HT@O3
HTEO, 2H + TeO,
K1 = 2 x 10
K2 =1 x 10-*
Tellurous
![а. HF (aq) + CIO (aq) 2D F (aq) + HСIO(ag)
The equilibrium lies predominantly to the right.
The equilibrium lies predominantly to the left.
Ni(H,O), OH * (aq) + HPO,* (aq) = [Ni(H,O)* (aq) + PO,* (aq)
O The equilibrium lies predominantly to the right.
O The equilibrium lies predominantly to the left.
с. NHa* (аq) + H,РО (аq) 2 NH3 (аq) + H;PO4(аq)
The equilibrium lies predominantly to the right.
O The equilibrium lies predominantly to the left.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6b655049-7826-439f-8581-abd316b9e58a%2F10c82c08-0942-4029-a9cc-d0468ba35ad4%2Fyolp4ut_processed.png&w=3840&q=75)
Transcribed Image Text:а. HF (aq) + CIO (aq) 2D F (aq) + HСIO(ag)
The equilibrium lies predominantly to the right.
The equilibrium lies predominantly to the left.
Ni(H,O), OH * (aq) + HPO,* (aq) = [Ni(H,O)* (aq) + PO,* (aq)
O The equilibrium lies predominantly to the right.
O The equilibrium lies predominantly to the left.
с. NHa* (аq) + H,РО (аq) 2 NH3 (аq) + H;PO4(аq)
The equilibrium lies predominantly to the right.
O The equilibrium lies predominantly to the left.
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