Reaction 3 Mass of NaOH Initial temperature Final temperature 36 C 1. Calculate the temperature change (AT) for the reaction. 0.25 g 27.3 C 2. Assuming the mass(m) of the reaction mixture = 0.25 g, and the specific heat (c) = 1.00 cal/g °C, calculate the heat (q) released by the reaction using the formula q = mc(AT). 3. Convert the grams of NaOH used to moles using the molar mass of NaOH (40 g/mol). 4. Divide q/mol NaOH to get the heat of the reaction 3 (ΔΗ3).
Reaction 3 Mass of NaOH Initial temperature Final temperature 36 C 1. Calculate the temperature change (AT) for the reaction. 0.25 g 27.3 C 2. Assuming the mass(m) of the reaction mixture = 0.25 g, and the specific heat (c) = 1.00 cal/g °C, calculate the heat (q) released by the reaction using the formula q = mc(AT). 3. Convert the grams of NaOH used to moles using the molar mass of NaOH (40 g/mol). 4. Divide q/mol NaOH to get the heat of the reaction 3 (ΔΗ3).
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Can you help me solve 2,3 and 4?
Transcribed Image Text:Reaction 3
0.25 g
27.3 C
Mass of NaOH
Initial temperature
Final temperature
36 C
1. Calculate the temperature change (AT) for the
reaction.
2. Assuming the mass (m) of the reaction mixture =
0.25 g, and the specific heat (c) = 1.00 cal/g °C,
calculate the heat (q) released by the reaction using
the formula q = mc(AT).
3. Convert the grams of NaOH used to moles using
the molar mass of NaOH (40 g/mol).
4. Divide q/mol NaOH to get the heat of the reaction
3 (ΔΗ3).
Expert Solution
Step 1
Given that,
The mass of the solution is m = 0.25 g,
The initial temperature is T1 = 27.3°C,
The final temperature is T2 = 36°C,
1. So, the temperature change is ∆T = (T2 - T1) = (36-27.3)°C = 8.7°C.
We have to calculate
2. The heat released due to the reaction (q).
3. The moles of NaOH.
4. The heat of the reaction (∆H3).
Formula: q = mC(∆T).
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Why is the Q a negative if it's suppose to be positive?
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