<STARTING AMOUNTXA brine solution is 3.50% NaCl by mass. Given that its density is 1.071 g/mL, determine the quantity of liters of solution that contains 5.00 moles of NaCl5.00ADD FACTOR0.1*( )3.501035.45Question 29 of 331.0710.018.03 x 10221000100ANSWER7.8022.990.0156L solution g NaCl/mL g solution mL solutionkg solutiong NaCl/g solution58.446.022 x 10230.0780moles of NaClmol NaClRESET0.00121g NaCl1.56

Mass percent of brine = 3.50 % NaCl by massDensity of solution = 1.071 gm/ml Moles of NaCl = 5.00 moleMolar mass of NaCl = 58.44 g.mole-1Weight of NaCl in 5 mole NaCl = mole × molar mass = 5.00 mole × 58.44 g.mole-1 = 292.2 gmMass% = (mass of NaCl / mass of solution)×100 3.50 = (292.2 / Msolution ) ×100 Msolution = (292.2 / 3.50 )×100 = 8348.6 gmVolume of solution = Msolution / density = 8348.6 g / 1.071 g.ml-1 = 7795.14 ml = 7.80 LVolume of solution is 7.80 L

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A brine solution is 3.50 % NaCl by mass. Given that its density is 1.071 g/mL , determine the quantity of liters of solution that contains 5.00 moles of NaCl

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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