Reaction 2: Bicarbonate (acting as an acid) reacts with water (acting as a base). HCO3 + H₂O = acid base Reaction 1 is more favorable. Reaction 2 is more favorable. Key Which statement correctly describes the relative favorability of these reactions in an aqueous solution of bicarbonate? Both reactions are equally favorable. Favorability cannot be determined. =

Chemistry
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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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This
example demonstrates how pk, can be used to help determine the favorability of a reaction.
Keq is the equilibrium constant and is usually referred to as K₁ in acid-base reactions. Given the pK, of an acid, you can
calculate K by taking its antilog.
Species
H₂O
HCO3
H₂CO3
H₂O+
HCO3 + H₂O =
base
acid
pK₁
15.74
10.33
6.35
-1.74
Complete the balanced equations for the equilibria given in reaction 1 and reaction 2. Then use the pK₂ values in the table to
calculate Keq for each reaction, where the Keq expression includes [H₂O]. Be sure to enter Keq in proper scientific notation.
Reaction 1: Bicarbonate (acting as a base) reacts with water (acting as an acid).
Kca
=
Transcribed Image Text:This example demonstrates how pk, can be used to help determine the favorability of a reaction. Keq is the equilibrium constant and is usually referred to as K₁ in acid-base reactions. Given the pK, of an acid, you can calculate K by taking its antilog. Species H₂O HCO3 H₂CO3 H₂O+ HCO3 + H₂O = base acid pK₁ 15.74 10.33 6.35 -1.74 Complete the balanced equations for the equilibria given in reaction 1 and reaction 2. Then use the pK₂ values in the table to calculate Keq for each reaction, where the Keq expression includes [H₂O]. Be sure to enter Keq in proper scientific notation. Reaction 1: Bicarbonate (acting as a base) reacts with water (acting as an acid). Kca =
Reaction 2: Bicarbonate (acting as an acid) reacts with water (acting as a base).
HCO3 + H₂O =
acid
base
Reaction 1 is more favorable.
Reaction 2 is more favorable.
Key
Which statement correctly describes the relative favorability of these reactions in an aqueous solution of bicarbonate?
Both reactions are equally favorable.
Favorability cannot be determined.
=
Transcribed Image Text:Reaction 2: Bicarbonate (acting as an acid) reacts with water (acting as a base). HCO3 + H₂O = acid base Reaction 1 is more favorable. Reaction 2 is more favorable. Key Which statement correctly describes the relative favorability of these reactions in an aqueous solution of bicarbonate? Both reactions are equally favorable. Favorability cannot be determined. =
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