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Mg(OH)2 + H3PO4→ Mg3(PO«)2 + H2O

Mg(OH)2 + H3PO4→ Mg3(PO«)2 + H2O

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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The image shows an unbalanced chemical equation that needs to be balanced. The equation is as follows: __Mg(OH)₂ + __H₃PO₄ → __Mg₃(PO₄)₂ + __H₂O Steps to balance the equation: 1. **Identify the number of each type of atom on both sides of the equation.** - **Left Side:** - Mg: 1 - O: 2 (in Mg(OH)₂) - H: 2 (in Mg(OH)₂) + 3 (in H₃PO₄) = 5 - P: 1 - **Right Side:** - Mg: 3 - O: 8 (in Mg₃(PO₄)₂) - H: 2 (in H₂O) - P: 2 2. **Balance the magnesium atoms by placing a coefficient of 3 in front of Mg(OH)₂:** 3Mg(OH)₂ + __H₃PO₄ → Mg₃(PO₄)₂ + __H₂O 3. **Balance the phosphorus atoms by placing a coefficient of 2 in front of H₃PO₄:** 3Mg(OH)₂ + 2H₃PO₄ → Mg₃(PO₄)₂ + __H₂O 4. **Balance the hydrogen atoms by placing a coefficient of 6 in front of H₂O:** 3Mg(OH)₂ + 2H₃PO₄ → Mg₃(PO₄)₂ + 6H₂O 5. **Verify the balance:** - **Left Side:** - Mg: 3 - O: 6 + 8 = 14 - H: 6 + 6 = 12 - P: 2 - **Right Side:** - Mg: 3 - O: 8 + 6 = 14 - H: 12 - P: 2 The balanced chemical equation is: 3Mg(OH)₂ + 2H₃PO₄ → Mg₃(PO₄)₂ + 6H₂O
Transcribed Image Text:The image shows an unbalanced chemical equation that needs to be balanced. The equation is as follows: __Mg(OH)₂ + __H₃PO₄ → __Mg₃(PO₄)₂ + __H₂O Steps to balance the equation: 1. **Identify the number of each type of atom on both sides of the equation.** - **Left Side:** - Mg: 1 - O: 2 (in Mg(OH)₂) - H: 2 (in Mg(OH)₂) + 3 (in H₃PO₄) = 5 - P: 1 - **Right Side:** - Mg: 3 - O: 8 (in Mg₃(PO₄)₂) - H: 2 (in H₂O) - P: 2 2. **Balance the magnesium atoms by placing a coefficient of 3 in front of Mg(OH)₂:** 3Mg(OH)₂ + __H₃PO₄ → Mg₃(PO₄)₂ + __H₂O 3. **Balance the phosphorus atoms by placing a coefficient of 2 in front of H₃PO₄:** 3Mg(OH)₂ + 2H₃PO₄ → Mg₃(PO₄)₂ + __H₂O 4. **Balance the hydrogen atoms by placing a coefficient of 6 in front of H₂O:** 3Mg(OH)₂ + 2H₃PO₄ → Mg₃(PO₄)₂ + 6H₂O 5. **Verify the balance:** - **Left Side:** - Mg: 3 - O: 6 + 8 = 14 - H: 6 + 6 = 12 - P: 2 - **Right Side:** - Mg: 3 - O: 8 + 6 = 14 - H: 12 - P: 2 The balanced chemical equation is: 3Mg(OH)₂ + 2H₃PO₄ → Mg₃(PO₄)₂ + 6H₂O
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