reaences to access important values if needed for this question.Consider the reaction:FeO3(s)+2Al(s)Al₂Os(s)+2Fe(s)Using standard absolute entropies at 298 K, calculate the entropy change for the system when 2.22 moles of Fez Os (s) react at standardconditions.Substance S (J/K mol)ASsystemFez Os(s)87.4Al(s)28.3Al₂O3(s)50.9Fe(s)27.8J/K

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Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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calculate ΔS rxn (standrad entropy) and Δ Ssurr for the reactions and determine if each is spontaneous at 25 degrees celsius.
Consider the reaction2H2S(g) + 3O2(g)2H2O(l) + 2SO2(g)for which H° = -1.124×103 kJ and S° = -390.7 J/K at 298.15 K.(1) Calculate the entropy change of the UNIVERSE when 2.296 moles of H2S(g) react under standard conditions at 298.15 K.Suniverse =____________ J/K(2) Is this reaction reactant or product favored under standard conditions? (3) If the reaction is product favored, is it enthalpy favored, entropy favored, or favored by both enthalpy and entropy? If the reaction is reactant favored choose 'reactant favored'.
ellus_engine.html?ClassID=1246112631# dent Orie. Using the data below, calculate the entropy for the decomposition of sodium bicarbonate. 2NaHCO3(s) → Na»CO3(s) + H2O(g) + CO2(g) Compounds S (J/mol-K) AHf° (kJ/mol) NaHCO,(s) Na,CO,(s) Co,(g) H,0(g) ASxn = [ ? ] J/K 102 -948 136 -1131 214 -394 189 -242 Enter either a + or - sign AND the magnitude. Entropy (J/K) Enter
Calculate ASsurr and ASuniverse for a reaction. Consider the reaction H₂S(g) + 2H₂O(1)→→3H₂(g) + SO₂(g) Using standard thermodynamic data (in the Chemistry References), calculate the entropy change of the surroundings and the universe at 25°C. AS surroundings = ASuniverse J/K J/K where ASO = 294.7 J/K rxn
Predict which member of each of the following pairs hasthe greater standard entropy at 25°C: (a) Sc(s) or Sc(g),(b) NH3(g) or NH3(aq), (c) O2(g) or O3(g), (d) C(graphite)or C(diamond). find the standardentropy of each substance.
Consider the reactionFe2O3(s) + 2Al(s)Al2O3(s) + 2Fe(s)for which H° = -851.5 kJ and S° = -37.00 J/K at 298.15 K.(1) Calculate the entropy change of the UNIVERSE when 1.631 moles of Fe2O3(s) react under standard conditions at 298.15 K.Suniverse = _______ J/K(2) Is this reaction reactant or product favored under standard conditions? (3) If the reaction is product favored, is it enthalpy favored, entropy favored, or favored by both enthalpy and entropy? If the reaction is reactant favored choose 'reactant favored'.
Consider the reaction: 4HCl(g) + O₂(g) → 2H₂O(g) + 2Cl₂ (g) Using standard absolute entropies at 298 K, calculate the entropy change for the system when 1.69 moles of HCl(g) react at standard conditions. AS⁰ Substance So (J/K mol) HCl(g) 186.9 O2(g) 205.1 H₂O(g) 188.8 Cl₂ (g) 223.1 system = J/K
Consider the reaction: 2H₂S(g) + 302 (g) → 2H₂O(1) + 2SO2 (g) Using standard absolute entropies at 298 K, calculate the entropy change for the system when 1.90 moles of H₂S(g) react at standard conditions. AS⁰ system Substance So (J/K mol) H₂S(g) 205.8 O₂(g) 205.1 H₂O(l) 69.9 SO₂(g) 248.2 = J/K
Consider the reaction: Fe2O3(s) + 2Al(s) → Al2O3 (s) + 2Fe(s) Using standard thermodynamic data at 298 K, calculate the entropy change for the surroundings when 2.00 moles of Fe₂O3(s) react at standard conditions. AS⁰ Substance AH (kJ/mol) Fe₂O3(s) -824.2 Al(s) 0.0 Al2O3(s) -1675.7 Fe(s) 0.0 surroundings J/K
Calculate entropy change of a sample of 20 g of ice when it melts at 0oC under pressure of 1 atm. (fus H (H2O) = 6.0 kJ mol-1)
Enter your answer in the provided box. Calculate the standard entropy change for the following reaction at 25°C. 2 Al(s) + 3 ZnO(s) → Al₂O3(s) + 3 Zn(s) Substance Al(s) Al³+ (aq) Al₂O3(s) Zn(s) Zn²+ (aq) ZnO(s) J/K Sº (J/K mol) 28.3 -313.38 50.99 41.6 -106.48 43.9 27
For the given processes, determine if AHxn and ASin are positive, negative, or zero. CH₂(g) +20₂(g) - CO₂(g) + 2 H₂O(g) AH;xn= zero negative O positive CO₂ (s) → CO₂(g) AHin O positive zero negative ASin = positive zero negative ASin = zero positive negative Callioneral Chemistry | Pub

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