Raw data in the table below come from an independent-measures experiment comparing three different treatment conditions.Treatment 10103X=1Select the null hypothesis for the statistical test:H1 H2 H3 H4Treatment 21412X=2To evaluate the effect of the independent variable, researchers conducted the independent-measures one-way ANOVA. They computed the sum of squares between groups to be 15.5 and the sum ofsquares within groups 14.75.OX,₁ =X₂=X₂○ ×₁=X₂=X₂=X₁μ1 = μ2 = μ3Treatment 33345X=3.75

Analysis of Variance (ANOVA) is a statistical formula used to compare variances across the means (or…

Answered: Raw data in the table below come from…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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You are conducting a study to see if the proportion of men over 50 who regularly have their prostate examined is significantly different from 0.25. You use a significance level of α=0.01α=0.01. H0:p=0.25H0:p=0.25 H1:p≠0.25H1:p≠0.25You obtain a sample of size n=687n=687 in which there are 143 successes.What is the test statistic for this sample? (Report answer accurate to three decimal places.)test statistic = What is the p-value for this sample? (Report answer accurate to four decimal places.)p-value =
The following results are from an independent-measures, two-factor study with n = 5 participants in each treatment condition. Use a two-factor ANOVA with α = .05 to evaluate the main effects and the interaction. Include a source table for your ANOVA.
You are conducting a study to see if the accuracy rate for fingerprint identification is significantly less than 0.13. You use a significance level of α=0.05α=0.05. H0:p=0.13H0:p=0.13 H1:p<0.13H1:p<0.13You obtain a sample of size n=632 in which there are 76 successes.What is the test statistic for this sample? (Report answer accurate to three decimal places.)test statistic = What is the p-value for this sample? (Report answer accurate to four decimal places.)p-value =
The following data represent the results from an independent-measures study comparing two treatment conditions. Treatment Treatment One Two 5.5 4.4 6.7 4.2 6.1 5.3 6.7 5.8 6.5 Using SPSS, run the independent-measures single-factor ANOVA for this data: F-ratio: p-value: Now, run the independent-measures t test on the same data: t-statistic: p-value: What do you observe about the p-values? What is the relationship between the F-ratio and the t-statistic? > Next Question M
Test the claim that the proportion of people who own cats is significantly different than 80% at the 0.1 significance level.The null and alternative hypothesis would be: H0:μ=0.8H0:μ=0.8H1:μ≠0.8H1:μ≠0.8 H0:p=0.8H0:p=0.8H1:p≠0.8H1:p≠0.8 H0:p≤0.8H0:p≤0.8H1:p>0.8H1:p>0.8 H0:p≥0.8H0:p≥0.8H1:p<0.8H1:p<0.8 H0:μ≤0.8H0:μ≤0.8H1:μ>0.8H1:μ>0.8 H0:μ≥0.8H0:μ≥0.8H1:μ<0.8H1:μ<0.8 The test is: right-tailed left-tailed two-tailed Based on a sample of 200 people, 87% owned catsThe p-value is: (to 2 decimals)Based on this we: Reject the null hypothesis Fail to reject the null hypothesis
Three treatments are compared for the treatment of in a between-subjects study. The following table of results were created to compare the three different treatment options. Treatment 1 Treatment 2 Treatment 3 n = 5 n = 5 n = 5 M = 2 M = 5 M = 8 N = 15 T = 10 T = 25 T = 40 G = 75 SS = 64 SS = 80 SS = 96 ΣX2 = 705 Use an ANOVA with α = .05 to determine whether there are any significant differences among the three treatment means. Calculate η2 as a measure of effect size. State the results as they would appear in a research report.
You are conducting a study to see if the proportion of voters who prefer Candidate A is significantly less than 0.75. You use a significance level of α=0.05      H0:p=0.75      H1:p<0.75You obtain a sample of size 223 in which there are 164 successes.What is the test statistic for this sample? (Report answer accurate to 3 decimal places.)What is the p-value for this sample? (Report answer accurate to 4 decimal places.)This test statistic leads to a decision to reject the null accept the null fail to reject the null As such, the final conclusion is that there is sufficient evidence to conclude that the proportion of voters who prefer Candidate A is less than 0.75. there is not sufficient evidence to conclude that the proportion of voters who prefer Candidate A is less than 0.75. there is sufficient evidence to conclude that the proportion of voters who prefer Candidate A is equal to 0.75. there is not sufficient evidence to con
The following data summarize the results from an independent-measures study comparing three treatment conditions. Treatment I       II       III N = 12    3   5 6    G = 60    5   5 10    ∑X2 = 392   3 1    10   1 5 6 x̅1 = 3   x̅2 = 4   x̅3 = 8      T1 = 12   T2 = 16   T3 =32…
You are conducting a study to see if the accuracy rate for fingerprint identification is significantly more than 0.24. You use a significance level of α=0.001α=0.001.      H0:p=0.24H0:p=0.24      H1:p>0.24H1:p>0.24You obtain a sample of size n=383n=383 in which there are 100 successes.What is the test statistic for this sample? (Report answer accurate to three decimal places.)test statistic = What is the p-value for this sample? (Report answer accurate to four decimal places.)p-value =
Test the claim that the proportion of men who own cats is significantly different than the proportion of women who own cats at the 0.2 significance level.The null and alternative hypothesis would be: H0:μM=μFH0:μM=μFH1:μM<μFH1:μM<μF H0:pM=pFH0:pM=pFH1:pM<pFH1:pM<pF H0:pM=pFH0:pM=pFH1:pM≠pFH1:pM≠pF H0:pM=pFH0:pM=pFH1:pM>pFH1:pM>pF H0:μM=μFH0:μM=μFH1:μM>μFH1:μM>μF H0:μM=μFH0:μM=μFH1:μM≠μFH1:μM≠μF The test is: right-tailed left-tailed two-tailed Based on a sample of 40 men, 25% owned catsBased on a sample of 20 women, 30% owned catsThe test statistic is: (to 2 decimals)The p-value is: (to 2 decimals)Based on this we: Reject the null hypothesis Fail to reject the null hypothesis
Fil 10. A small pilot study is conducted to investigate the effect of a nutritional supplement on total body weight. Six participants agree to take the nutritional supplement. To assess its effect on body weight, weights are measured before starting the supplementation and then after 6 weeks. The data are shown below. Is there a significant increase in body weight following supplementation? Run the test at a 5% level of significance. Demonstrate the five steps for hypothesis testing and explain your results. Subject İnitial Weight Weight after 6 Weeks 1 155 157 2 142 145 3 176 180 4 180 175 210 209 6. 125 126
You are conducting a study to see if the proportion of men over 50 who regularly have their prostate examined is significantly more than 0.69. You use a significance level of α=0.01α=0.01. H0:p=0.69H0:p=0.69 H1:p>0.69H1:p>0.69You obtain a sample of size n=445n=445 in which there are 338 successes.What is the p-value for this sample? (Report answer accurate to four decimal places.)p-value = The p-value is... less than (or equal to) αα greater than αα This p-value leads to a decision to... reject the null accept the null fail to reject the null As such, the final conclusion is that... There is sufficient evidence to warrant rejection of the claim that the proportion of men over 50 who regularly have their prostate examined is more than 0.69. There is not sufficient evidence to warrant rejection of the claim that the proportion of men over 50 who regularly have their prostate examined is more than 0.69. The sample data support the claim that the proportion of men…

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