Rather than having constant acceleration, an object accelerates along the ver-tical (y) axis with a non-constant acceleration given byat) = (2) in ().mwhere the acceleration is in the +y direction when a is positive. Assume theinitial velocity is zero and the initial position is at y = 0.(a) What is the velocity of the object as a function of time, v(t)? What is theposition of the object as a function of time, y(t)?

Answered: Image /qna-images/answer/a260f982-8e0a-4e61-8e5c-10a3d1d36ba6.jpg

Answered: Rather than having constant…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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The position of a particle moving along an x axis is given by x = 12.0t2 - 2.00t°, where x is in meters and t is in seconds. Determine (a) the position, (b) the velocity, and (c) the acceleration of the particle at t = 3.00 s. (d) What is the maximum positive coordinate reached by the particle and (e) at what time is it reached? (f) What is the maximum positive velocity reached by the particle and (g) at what time is it reached? (h) VWhat is the acceleration of the particle at the instant the particle is not moving (other than at t = 0)? (i) Determine the average velocity of the particle between t = 0 and t 3.00 s. (a) Number i Units (b) Number Units (c) Number i Units (d) Number Units (e) Number Units (f) Number Units (g) Number i Units (h) Number i Units (i) Number i Units
Suppose you are standing at the edge of a 200 meter tall cliff and are in the habit of dropping objects from great heights. So, you drop a rock off of the cliff. (a) What are the initial position s(0), velocity v(0), and acceleration a(0) of the rock? b) Use your answers from part (a) to define functions s(t), v(t), and a(t) describing the position, velocity, and acceleration, respectively, after t seconds. (c) How long will it take for the rock to hit the ground? How fast is it falling when it hits?
The position of a particle moving along an x axis is given by x = 16.0t2 - 5.00t³, where x is in meters and t is in seconds. Determine (d) What is the maximum positive coordinate reached by the particle and (e) at what time is it reached? (f) What is the maximum positive velocity reached by the particle (i) Determine the average velocity of the particle between t = 0 and t = 6.00 s.
The froghopper Philaenus spumarius is supposedly the best jumper in the animal kingdom. To start a jump, this insect can accelerate at 4.00 km/s2 over a distance of 2.0 mm as it straightens its specially designed "jumping legs." (a) Find the upward velocity with which the insect takes off. m/s (b) In what time interval does it reach this velocity? ms (c) How high would the insect jump if air resistance were negligible? The actual height it reaches is about 70 cm, so air resistance must be a noticeable force on the leaping froghopper. m Need Help? Read It
When a particle is projected vertically upwards with an initial velocity of ϑ0, it experiences an acceleration shown below, where g is the acceleration due to gravity, k is a constant and ϑ is the velocity of the particle. Determine the maximum height reached by the particle in m when k = 0.5 and initial velocity ϑ0 =10 m/s.
The acceleration function (in m/s2) and the initial velocity are given for a particle moving along a line.Constants b and c are positive. a(t) = bt + c, and initial velocity v(0)> 0 ; where 0 ≤ t ≤ x (a) Find the velocity at time t.v(t) = m/s(b) Find the distance traveled during the given time interval.distance (t) = m
A particle moves along the x axis. It is initially at the position 0.240 m, moving with velocity 0.150 m/s and acceleration -0.240 m/s?. Suppose it moves with constant acceleration for 4.80 s. (a) Find the position of the particle after this time. (b) Find its velocity at the end of this time interval. m/s We take the same particle and give it the same initial conditions as before. Instead of having a constant acceleration, it oscillates in simple harmonic motion for 4.80 s around the equilibrium position x = 0. Hint: the following problems are very sensitive to rounding, and you should keep all digits in your calculator. (c) Find the angular frequency of the oscillation. Hint: in SHM, a is proportional to x. /s (d) Find the amplitude of the oscillation. Hint: use conservation of energy. m (e) Find its phase constant e, if cosine is used for the equation of motion. Hint: when taking the inverse of a trig function, there are always two angles but your calculator will tell you only one…
The position of a particle moving along an x axis is given by x = 13.0t2 - 6.00t3, where x is in meters and t is in seconds. Determine (a) the position, (b) the velocity, and (c) the acceleration of the particle at t = 4.00 s. (d) What is the maximum positive coordinate reached by the particle and (e) at what time is it reached? (f) What is the maximum positive velocity reached by the particle and (g) at what time is it reached? (h) What is the acceleration of the particle at the instant the particle is not moving (other than at t = 0)? (i) Determine the average velocity of the particle between t = 0 and t = 4.00 s.(a).=-176m(b).=-184m/s (c).=-118.0m/s^2 (d).=9.041m (e).=1.444s (f).=9.389m/s (g).=0.722sPlease help me with h and i.

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