The position of a particle moving along the x axis may be determined from the expression x(t) = bt + ct?, where b = 3.20 m/s, c = 2.00 m/s?, and x will be in meters when t is in seconds. (a) Which of the following is the correct expression for the position of the particle at the time t + At? x(t + At) = bt + bAt O x(t + At) = bt + bAt – ct² – 2ctat – c(At)? x(t + At) = ct + cAt + bt2 + 2btat + b(At)2 O x(t + At) = bt + bAt + ct2 + 2ctAt + c(At)2 x(t + At) = ct² + 2ctAt + c(At)? (b) Which of the following is the correct expression for the displacement of the particle between the time t and t+ At? Ax(t →t+ AAt) = bt + 2ctAt – cAt O Ax(t t+ At) = bat + 2ctAt - c(At)? Ax(t t + At) = btat + 2ctAt + cAt Ax(t t + At) = bAt + 2cAt + 2c(At)? O Ax(t -t + At) = bAt + 2ctAt + C(At)? (c) Which of the following is the correct expression for the limit of Ax/At as At approaches zero? Ax = bt + 2ct lim At-0 At lim AX = bt + ct At0 At Дх = b + 2c lim At -0 At Ax = b + 2ct lim At-0 At Дх = b + ct lim At-0 At (d) Determine the instantaneous velocity of the particle at the time t = 2.00 s. m/s
The position of a particle moving along the x axis may be determined from the expression x(t) = bt + ct?, where b = 3.20 m/s, c = 2.00 m/s?, and x will be in meters when t is in seconds. (a) Which of the following is the correct expression for the position of the particle at the time t + At? x(t + At) = bt + bAt O x(t + At) = bt + bAt – ct² – 2ctat – c(At)? x(t + At) = ct + cAt + bt2 + 2btat + b(At)2 O x(t + At) = bt + bAt + ct2 + 2ctAt + c(At)2 x(t + At) = ct² + 2ctAt + c(At)? (b) Which of the following is the correct expression for the displacement of the particle between the time t and t+ At? Ax(t →t+ AAt) = bt + 2ctAt – cAt O Ax(t t+ At) = bat + 2ctAt - c(At)? Ax(t t + At) = btat + 2ctAt + cAt Ax(t t + At) = bAt + 2cAt + 2c(At)? O Ax(t -t + At) = bAt + 2ctAt + C(At)? (c) Which of the following is the correct expression for the limit of Ax/At as At approaches zero? Ax = bt + 2ct lim At-0 At lim AX = bt + ct At0 At Дх = b + 2c lim At -0 At Ax = b + 2ct lim At-0 At Дх = b + ct lim At-0 At (d) Determine the instantaneous velocity of the particle at the time t = 2.00 s. m/s
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Transcribed Image Text:The position of a particle moving along the x axis may be determined from the expression x(t) = bt + ct2, where b
3.20 m/s, c = 2.00 m/s?, and x will be in meters when t is in seconds.
(a) Which of the following is the correct expression for the position of the particle at the time t + At?
x(t + At) = bt + bAt
X(t + Δt)
= bt + bAt
ct2 – 2ctAt – c(At)2
|
x(t + Δt)
= ct + cAt + bt? + 2btAt + b(At)?
x(t + Δt)
= bt + bAt + ct2 + 2ctAt + c(At)2
x(t + Δt)
ct2 + 2ctAt + c(At)²
(b) Which of the following is the correct expression for the displacement of the particle between the time t and t + At?
Ax(t -
→ t + At) = bt + 2ctAt
cAt
Ax(t → t + At) = bAt + 2ctAt – c(At)?
-
O Ax(t →t + At) = btAt + 2ctAt + cAt
Ax(t → t + At) = bAt + 2cAt + 2c(At)2
Ax(t →t + At) = bAt + 2ctAt + c(At)²
(c) Which of the following is the correct expression for the limit of Ax/At as At approaches zero?
Ax
lim
= bt + 2ct
At →0 At
Ax
= bt + ct
lim
At →0 At
Ax
b + 2c
lim
At →0 At
Ax
= b + 2ct
lim
At →0 At
Дх
= b + ct
lim
At →0 At
(d) Determine the instantaneous velocity of the particle at the time t = 2.00 s.
m/s
O O O O O
Expert Solution

Step 1
Given data
The position of the particle is x (t) = bt + ct2
The constant b = 3.20 m/s
The constant c = 2 m/s2
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