The function s(t) describes the motion of a particle along a line. s(t) = t3 - 11t² + 35t – 250 (a) Find the velocity function v(t) of the particle at any time t2 0. v(t) = (b) Identify the time interval(s) on which the particle is moving in a positive direction. (Enter your answer using interval notation.) (c) Identify the time interval(s) on which the particle is moving in a negative direction. (Enter your answer using interval notation.) (d) Identify the time(s) at which the particle changes direction. (Enter your answers as a comma-separated list.)

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### Problem Statement

The function \( s(t) \) describes the motion of a particle along a line.

\[ s(t) = t^3 - 11t^2 + 35t - 250 \]

1. **(a)** Find the velocity function \( v(t) \) of the particle at any time \( t \geq 0 \).
   - \( v(t) = \underline{\hspace{4cm}} \)

2. **(b)** Identify the time interval(s) on which the particle is moving in a positive direction. (Enter your answer using interval notation.)
   - \(\underline{\hspace{8cm}}\)

3. **(c)** Identify the time interval(s) on which the particle is moving in a negative direction. (Enter your answer using interval notation.)
   - \(\underline{\hspace{8cm}}\)

4. **(d)** Identify the time(s) at which the particle changes direction. (Enter your answers as a comma-separated list.)
   - \( t = \underline{\hspace{6cm}} \)

### Explanation

In this exercise, we are given a function that represents the motion of a particle along a line, and we are required to:

1. **Calculate the Velocity Function**: Derive the velocity function from the given position function \( s(t) \).

2. **Determine Positive Movement Intervals**: Identify time intervals where the particle moves in a positive direction.

3. **Determine Negative Movement Intervals**: Identify time intervals where the particle moves in a negative direction.

4. **Identify Points of Direction Change**: Find the times at which the particle changes its direction.

The solution involves using calculus to derive the velocity function \( v(t) = s'(t) \), analyzing the sign of \( v(t) \) to identify intervals of positive and negative motion, and determining when changes in direction occur by finding where \( v(t) = 0 \) and changes sign.
Transcribed Image Text:### Problem Statement The function \( s(t) \) describes the motion of a particle along a line. \[ s(t) = t^3 - 11t^2 + 35t - 250 \] 1. **(a)** Find the velocity function \( v(t) \) of the particle at any time \( t \geq 0 \). - \( v(t) = \underline{\hspace{4cm}} \) 2. **(b)** Identify the time interval(s) on which the particle is moving in a positive direction. (Enter your answer using interval notation.) - \(\underline{\hspace{8cm}}\) 3. **(c)** Identify the time interval(s) on which the particle is moving in a negative direction. (Enter your answer using interval notation.) - \(\underline{\hspace{8cm}}\) 4. **(d)** Identify the time(s) at which the particle changes direction. (Enter your answers as a comma-separated list.) - \( t = \underline{\hspace{6cm}} \) ### Explanation In this exercise, we are given a function that represents the motion of a particle along a line, and we are required to: 1. **Calculate the Velocity Function**: Derive the velocity function from the given position function \( s(t) \). 2. **Determine Positive Movement Intervals**: Identify time intervals where the particle moves in a positive direction. 3. **Determine Negative Movement Intervals**: Identify time intervals where the particle moves in a negative direction. 4. **Identify Points of Direction Change**: Find the times at which the particle changes its direction. The solution involves using calculus to derive the velocity function \( v(t) = s'(t) \), analyzing the sign of \( v(t) \) to identify intervals of positive and negative motion, and determining when changes in direction occur by finding where \( v(t) = 0 \) and changes sign.
Expert Solution
Step 1

(a)

The velocity of the particle can be determined by differentiating the displacement function with respect to time.

vt=ddtstvt=ddtt3-11t2+35t-250vt=2t2-22t+35

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