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Rachel, a city employee, would like to make the claim that the average amount that residents spend per month on public transit fare is less than $140. Rachel samples 25 city residents and obtains a sample mean of $125.80 spent per month on public transit. At the 5% significance level, should Rachel reject or fail to reject the null hypothesis given the sample data below? Ho : µ = $140 per month; H. : µ < $140 per month • a = 0.05 (significance level) • test statistic = -0.52 Use the graph below to select the type of test (left-, right-, or two-tailed). Then set the a and the test statistic to determine the p-value. Use the results to determine whether to reject or fail to reject the null hyp esis. Alternatively, find the p-value using the table below: 0.00 0.01 0.02 0.03 0.04 0.05 0.06 0.07 0.08 0.09 -0.9 0.184 0.181 0.179 0.176 0.174 0.171 0.1690.166 0.164 0.161 -0.6 0.274 0.271 0.268 0.264 0.261 0.258 0.255 0.251 0.248 0.245 -0.5 0.309 0.305 0.302 0.298 0.2950.291 0.288 0.284 0.281 0.278 -0.4 0.345 0.341 0.3370.334 0.330 0.326 0.323 0.319 0.3160.312 -0.30.3820.378 0.3740.371 0.3670.363 0.359 0.356 0.352 0.348

Rachel, a city employee, would like to make the claim that the average amount that residents spend per month on public transit fare is less than $140. Rachel samples 25 city residents and obtains a sample mean of $125.80 spent per month on public transit. At the 5% significance level, should Rachel reject or fail to reject the null hypothesis given the sample data below? Ho : µ = $140 per month; H. : µ < $140 per month • a = 0.05 (significance level) • test statistic = -0.52 Use the graph below to select the type of test (left-, right-, or two-tailed). Then set the a and the test statistic to determine the p-value. Use the results to determine whether to reject or fail to reject the null hyp esis. Alternatively, find the p-value using the table below: 0.00 0.01 0.02 0.03 0.04 0.05 0.06 0.07 0.08 0.09 -0.9 0.184 0.181 0.179 0.176 0.174 0.171 0.1690.166 0.164 0.161 -0.6 0.274 0.271 0.268 0.264 0.261 0.258 0.255 0.251 0.248 0.245 -0.5 0.309 0.305 0.302 0.298 0.2950.291 0.288 0.284 0.281 0.278 -0.4 0.345 0.341 0.3370.334 0.330 0.326 0.323 0.319 0.3160.312 -0.30.3820.378 0.3740.371 0.3670.363 0.359 0.356 0.352 0.348

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter4: Equations Of Linear Functions
Section: Chapter Questions
Problem 8SGR
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Move the blue dot to choose the appropriate test Significance level = 0.05 a=0.01 a=0.025 a=0.05 a=0.1 p-value= 0.166 test statistic = 9 97 645 powered by desmos Select the correct answer below: O Reject the null hypothesis because the value of z is negative. O Do not reject the null hypothesis because |–0.52| > 0.05. O Reject the null hypothesis because the p-value 0.3015 is greater than the significance level a = 0.05. O Do not reject the null hypothesis because the p-value 0.3015 is greater than the significance level a = 0.05. O Reject the null hypothesis because |–0.52| > 0.05.
Transcribed Image Text:Move the blue dot to choose the appropriate test Significance level = 0.05 a=0.01 a=0.025 a=0.05 a=0.1 p-value= 0.166 test statistic = 9 97 645 powered by desmos Select the correct answer below: O Reject the null hypothesis because the value of z is negative. O Do not reject the null hypothesis because |–0.52| > 0.05. O Reject the null hypothesis because the p-value 0.3015 is greater than the significance level a = 0.05. O Do not reject the null hypothesis because the p-value 0.3015 is greater than the significance level a = 0.05. O Reject the null hypothesis because |–0.52| > 0.05.
Question Rachel, a city employee, would like to make the claim that the average amount that residents spend per month on public transit fare is less than $140. Rachel samples 25 city residents and obtains a sample mean of $125.80 spent per month on public transit. At the 5% significance level, should Rachel reject or fail to reject the null hypothesis given the sample data below? • Ho : µ = $140 per month; Ha : µ < $140 per month • a = 0.05 (significance level) • test statistic = -0.52 Use the graph below to select the type of test (left-, right-, or two-tailed). Then set the and the test statistic to determine the p-value. Use the results to determine whether to reject or fail to reject the null hypothesis. Alternatively, find the p-value using the table below: 0.00 0.01 0.02 0.03 0.04 0.05 0.06 0.07 0.08 0.09 -0.9 0.184 0.181 0.179 0.176 0.1740.171 0.1690.166 0.164 0.161 |-0.6 0.274 0.271 0.268 0.264 0.261 0.258 0.255 0.251 0.248 0.245 |-0.5 0.309 0.305 0.302 0.298 0.295 0.291 0.2880.2840.281 0.278 |-0.4 0.345 0.341 0.337 0.334 0.3300.326 0.323 0.319 0.316 o.312 -0.3 0.382 0.3780.374 0.371 0.367 0.363 0.359 0.356 0.352 0.348 Move the blue dot to choose the appropriate test Significance level = 0.01
Transcribed Image Text:Question Rachel, a city employee, would like to make the claim that the average amount that residents spend per month on public transit fare is less than $140. Rachel samples 25 city residents and obtains a sample mean of $125.80 spent per month on public transit. At the 5% significance level, should Rachel reject or fail to reject the null hypothesis given the sample data below? • Ho : µ = $140 per month; Ha : µ < $140 per month • a = 0.05 (significance level) • test statistic = -0.52 Use the graph below to select the type of test (left-, right-, or two-tailed). Then set the and the test statistic to determine the p-value. Use the results to determine whether to reject or fail to reject the null hypothesis. Alternatively, find the p-value using the table below: 0.00 0.01 0.02 0.03 0.04 0.05 0.06 0.07 0.08 0.09 -0.9 0.184 0.181 0.179 0.176 0.1740.171 0.1690.166 0.164 0.161 |-0.6 0.274 0.271 0.268 0.264 0.261 0.258 0.255 0.251 0.248 0.245 |-0.5 0.309 0.305 0.302 0.298 0.295 0.291 0.2880.2840.281 0.278 |-0.4 0.345 0.341 0.337 0.334 0.3300.326 0.323 0.319 0.316 o.312 -0.3 0.382 0.3780.374 0.371 0.367 0.363 0.359 0.356 0.352 0.348 Move the blue dot to choose the appropriate test Significance level = 0.01
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