QUESTIONS: 1. How many students does the teacher have? 2. What is the random variable in this activity? 3. What are the values of the random variable?

A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
icon
Related questions
Topic Video
Question
100%
ICS AND PROBABILITY
RAND & SECTION.
QUESTIONS:
1. How many students does the teacher have?
2. What is the random variable in this activity?
3. What are the values of the random variable?
4. Find the sum of the probability of the random variable (W). Is the answer a
coincidence or should this be expected? Briefly explain.
5. How many learners is/are only child?
6. What is the probability that a randomly-selected learner is an only child?
7. What is the chance that a randomly-selected learner has at most two siblings?
8-10. What is the probability that a randomly-selected learner has three or more
siblings? (Your two classmates Lisa and Felix tried to answer. Below are their
solutions.)
Felix
P(W > 3) = P(W = 3 orW = 4 or W = 5 or W = 7)
=P(W = 3) + P(W = 4) + P(W = 5) +P(W=7)
=0.1 + 0.06 + 0.02 + 0.02
Lisa
P(W > 3) = P(W = 4 or W = 5 or W = 7)
=P(W = 4) + P(W = 5) +P(W=7)
=0.06 + 0.02 + 0.02
=0.1 or 10%
=0.2 or 20%
Therefore, the probability of picking a learner
having 3 or more siblings out of 50 students is 0.10
or 10% of chance.
Therefore, the probability of picking a learner having
3 or more siblings out of 50 students is 0.20 or 20%
chance.
Who do you think got the correct answer? Briefly explain your answer.
11-15. What is the probability that a randomly-selected learner have at least 2
siblings? (Use the back page of this activity sheet for your solutions.)
Transcribed Image Text:ICS AND PROBABILITY RAND & SECTION. QUESTIONS: 1. How many students does the teacher have? 2. What is the random variable in this activity? 3. What are the values of the random variable? 4. Find the sum of the probability of the random variable (W). Is the answer a coincidence or should this be expected? Briefly explain. 5. How many learners is/are only child? 6. What is the probability that a randomly-selected learner is an only child? 7. What is the chance that a randomly-selected learner has at most two siblings? 8-10. What is the probability that a randomly-selected learner has three or more siblings? (Your two classmates Lisa and Felix tried to answer. Below are their solutions.) Felix P(W > 3) = P(W = 3 orW = 4 or W = 5 or W = 7) =P(W = 3) + P(W = 4) + P(W = 5) +P(W=7) =0.1 + 0.06 + 0.02 + 0.02 Lisa P(W > 3) = P(W = 4 or W = 5 or W = 7) =P(W = 4) + P(W = 5) +P(W=7) =0.06 + 0.02 + 0.02 =0.1 or 10% =0.2 or 20% Therefore, the probability of picking a learner having 3 or more siblings out of 50 students is 0.10 or 10% of chance. Therefore, the probability of picking a learner having 3 or more siblings out of 50 students is 0.20 or 20% chance. Who do you think got the correct answer? Briefly explain your answer. 11-15. What is the probability that a randomly-selected learner have at least 2 siblings? (Use the back page of this activity sheet for your solutions.)
STATISTICS
Directly answer on this bond paper. Write your NAME, TRACK/STRAN
ACTIVITY NO. 5: COMPUTING PROBABILITY CORRESPONDING TO
A GIVEN RANDOM VARIABLE
NAME:
SCORE:
TRACK/STRAND & SEC.:
(HOW MANY SIBLINGS DO THE LEARNERS HAVE)
In your Statistics class, the teacher wants to know the number of
siblings the learners have.
Teacher: How many of the class have 0 sibling?
Class: (There were 2 learners who raised their hands.)
Teacher: How many of you has 1 sibling?
Class: (There were 10 learners who raised their hands.)
This continues until 7 siblings. Suppose that we have the following
table of frequencies. Let us use W to represent the number of
sibling/s.
Probability of the Random Variable (W)
W= Number of siblings
Frequency
P(W)
2/50 = 0.04 = 4%
10/50= 0.2 = 20%
28/50=0.56 = 56%
5/50=0.1 = 10%
3/50=0.06 = 6%
1/50=0.02 = 2%
2
1
10
28
3
5
4
3
1
6.
7
1
1/50=0.02 = 2%
Total
Transcribed Image Text:STATISTICS Directly answer on this bond paper. Write your NAME, TRACK/STRAN ACTIVITY NO. 5: COMPUTING PROBABILITY CORRESPONDING TO A GIVEN RANDOM VARIABLE NAME: SCORE: TRACK/STRAND & SEC.: (HOW MANY SIBLINGS DO THE LEARNERS HAVE) In your Statistics class, the teacher wants to know the number of siblings the learners have. Teacher: How many of the class have 0 sibling? Class: (There were 2 learners who raised their hands.) Teacher: How many of you has 1 sibling? Class: (There were 10 learners who raised their hands.) This continues until 7 siblings. Suppose that we have the following table of frequencies. Let us use W to represent the number of sibling/s. Probability of the Random Variable (W) W= Number of siblings Frequency P(W) 2/50 = 0.04 = 4% 10/50= 0.2 = 20% 28/50=0.56 = 56% 5/50=0.1 = 10% 3/50=0.06 = 6% 1/50=0.02 = 2% 2 1 10 28 3 5 4 3 1 6. 7 1 1/50=0.02 = 2% Total
Expert Solution
steps

Step by step

Solved in 2 steps with 1 images

Blurred answer
Knowledge Booster
Discrete Probability Distributions
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, probability and related others by exploring similar questions and additional content below.
Similar questions
Recommended textbooks for you
A First Course in Probability (10th Edition)
A First Course in Probability (10th Edition)
Probability
ISBN:
9780134753119
Author:
Sheldon Ross
Publisher:
PEARSON
A First Course in Probability
A First Course in Probability
Probability
ISBN:
9780321794772
Author:
Sheldon Ross
Publisher:
PEARSON