Question There are two lines through the point (−1, 3) that are tangent to the curve x^2 + 4y^2 − 4x − 8y + 3 = 0. Find the equation of these two lines.  Answers tangent 1: x + 4 = 11 tangent 2: 11x + 4 = 1 Show me to get the answers by differentiation.

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Hi! I need help. Our book had shown the answers but I do not know how they got to those answers. Can you please show me the solution on how to get the answers using differentiation?

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There are two lines through the point (−1, 3) that are tangent to the curve x^2 + 4y^2 − 4x − 8y + 3 = 0. Find the equation of these two lines. 

Answers
tangent 1: x + 4 = 11
tangent 2: 11x + 4 = 1

Show me to get the answers by differentiation.

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