9w2 - 5w + 7 y = = 9w3/2 - 5w1/2+ 7w¯1/2. Vw Now, since the function is a sum of power functions, we can use the Power Rule to find its derivative. Recall that according to the Power Rule, the derivative of w", where n is any real number, is nw" . To use the Power Rule, we'll have to calculate the following. 3. - 1 = 1/2 1/2 1 -1 = -1/2 -1/2 - 1 = 2 -3/2 -3/2 Applying the power rule, we have the following. 27/2 Jw/2 -( 5/2 w-1/2+ |-7/2 w-3/2 y' = (27/2 5/2 V -7/2 V Step 3 Now we can conclude the following y' =
9w2 - 5w + 7 y = = 9w3/2 - 5w1/2+ 7w¯1/2. Vw Now, since the function is a sum of power functions, we can use the Power Rule to find its derivative. Recall that according to the Power Rule, the derivative of w", where n is any real number, is nw" . To use the Power Rule, we'll have to calculate the following. 3. - 1 = 1/2 1/2 1 -1 = -1/2 -1/2 - 1 = 2 -3/2 -3/2 Applying the power rule, we have the following. 27/2 Jw/2 -( 5/2 w-1/2+ |-7/2 w-3/2 y' = (27/2 5/2 V -7/2 V Step 3 Now we can conclude the following y' =
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Transcribed Image Text:9w2 – 5w + 7
y =
= 9w3/2 - 5w1/2+ 7w¯1/2.
Vw
Now, since the function is a sum of power functions, we can use the Power Rule to find its derivative. Recall that according to the Power Rule, the derivative of
w", where n is any real number, is nw" . To use the Power Rule, we'll have to calculate the following.
3
- 1 3=
1/2
1
-1 = -1/2
-1/2
- 1 = -3/2
-3/2
Applying the power rule, we have the following.
27/2 w/2-(
5/2 w-1/2+
|-7/2 w-3/2
y' = (27/2
5/2 V
-7/2 V
Step 3
Now we can conclude the following
y' =
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Transcribed Image Text:Step 4
Now recall the general version of the power rule, wheren is any real number.
-(x") = nx" - 1
%3D
xp
Applying this rule to each of our derivatives gives us the following.
-(x*) +5.
dx
= 4x3 + 15x2
%3D
xp
To conclude, state the result when the function f(x) = x(x + 5) is differentiated.
f'(x) =
%3D
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