WIN 8 2. The curve shown below has equation x2/3 + y2/3 = 4 and is called an Astroid. a) Use implicit differentiation to find the equation of the tangent line to this curve at the point (-1,-3√3). Graph the tangent line that you found on the figure below. d dx wlu 4+353= -IM d (x²2/3) + ax 9 2 -13 2-1/3 dy 3/3 dx +24 25½ 3 b) Find the point(s) where the tangent line has slope m = -1 3dy dx dy cx dy 4813 = 0 4 273 clx = -2 3x3 24-43 3 - 0 1 13-1/S X3x73 th =-(-353) / 5 冷: M - 11/3
WIN 8 2. The curve shown below has equation x2/3 + y2/3 = 4 and is called an Astroid. a) Use implicit differentiation to find the equation of the tangent line to this curve at the point (-1,-3√3). Graph the tangent line that you found on the figure below. d dx wlu 4+353= -IM d (x²2/3) + ax 9 2 -13 2-1/3 dy 3/3 dx +24 25½ 3 b) Find the point(s) where the tangent line has slope m = -1 3dy dx dy cx dy 4813 = 0 4 273 clx = -2 3x3 24-43 3 - 0 1 13-1/S X3x73 th =-(-353) / 5 冷: M - 11/3
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question
Please solve a and b thanks!
![2
2. The curve shown below has equation x2/3 + y2/3 = 4 and is called an Astroid.
a) Use implicit differentiation to find the equation of the tangent line to this curve at the point (-1,-3√3). Graph the
tangent line that you found on the figure below.
d
4
y
d'inst t
2_-> {t{"nat)
CUNG
8
d
dx
Ub
4+353=
d
(x²/3) + ²x4²
ax g
b) Find the point(s) where the tangent line has slope m = -1
x]2=52
2
X
។
+/zilady-20
=
dx
2415
3
-1/3, 2-1/3 dy
'+ dx
= £y£
dy
dx
dy
273
=
cx
x
3x²
24-43
113
-
= 0
13-1/5
Key"
Ya $x73
en
y's
хуз
=-(-355)1/5
-1'/3](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6b1ec9e1-71c5-41a7-88e5-1ec0b0e62692%2F7308d93e-f4e1-4d37-9196-90b9c6cbae1f%2Ft46ha1l_processed.jpeg&w=3840&q=75)
Transcribed Image Text:2
2. The curve shown below has equation x2/3 + y2/3 = 4 and is called an Astroid.
a) Use implicit differentiation to find the equation of the tangent line to this curve at the point (-1,-3√3). Graph the
tangent line that you found on the figure below.
d
4
y
d'inst t
2_-> {t{"nat)
CUNG
8
d
dx
Ub
4+353=
d
(x²/3) + ²x4²
ax g
b) Find the point(s) where the tangent line has slope m = -1
x]2=52
2
X
។
+/zilady-20
=
dx
2415
3
-1/3, 2-1/3 dy
'+ dx
= £y£
dy
dx
dy
273
=
cx
x
3x²
24-43
113
-
= 0
13-1/5
Key"
Ya $x73
en
y's
хуз
=-(-355)1/5
-1'/3
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