Question Help A large company employs workers whose IQs are distributed normally with mean 100 and standard deviation 7.5. Management uses this information to assign employees to projects that will be challenging, but not too challenging. What percent of employees would have IQs less than 91? Click here to see page 1 of the table for areas under the standard normal curve. Click here to see page 2 of the table for areas under the standard normal curve. The percentage of employees expected to have IQs less than 91 is %. (Round to the nearest tenth as needed.)

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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A large company employs workers whose IQs are distributed normally with a mean of 100 and a standard deviation of 7.5. Management uses this information to assign employees to projects that will be challenging, but not too challenging. What percent of employees would have IQs less than 91?

- [Click here to see page 1 of the table for areas under the standard normal curve.](#)
- [Click here to see page 2 of the table for areas under the standard normal curve.](#)

The percentage of employees expected to have IQs less than 91 is [ ]%.

(Round to the nearest tenth as needed.)
Transcribed Image Text:A large company employs workers whose IQs are distributed normally with a mean of 100 and a standard deviation of 7.5. Management uses this information to assign employees to projects that will be challenging, but not too challenging. What percent of employees would have IQs less than 91? - [Click here to see page 1 of the table for areas under the standard normal curve.](#) - [Click here to see page 2 of the table for areas under the standard normal curve.](#) The percentage of employees expected to have IQs less than 91 is [ ]%. (Round to the nearest tenth as needed.)
Find the percent of the total area under the standard normal curve between the following z-scores.

\( z = -1.3 \) and \( z = 0.7 \)

[Click here to see page 1 of the table for areas under the standard normal curve.](#)

[Click here to see page 2 of the table for areas under the standard normal curve.](#)

The percent of the total area between \( z = -1.3 \) and \( z = 0.7 \) is [ ]%.

(Round to the nearest tenth as needed.)
Transcribed Image Text:Find the percent of the total area under the standard normal curve between the following z-scores. \( z = -1.3 \) and \( z = 0.7 \) [Click here to see page 1 of the table for areas under the standard normal curve.](#) [Click here to see page 2 of the table for areas under the standard normal curve.](#) The percent of the total area between \( z = -1.3 \) and \( z = 0.7 \) is [ ]%. (Round to the nearest tenth as needed.)
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