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Consider a test of coordination that has a normal distribution, a mean of 50, and a standard deviation of 5. (a) How high a score would a person need to have to be in the top 3%? (b) Explain your answer to someone who has never had a course in statistics. Click here to view page 1 of the table. Click here to view page 2 of the table. Click here to view page 3 of the table. Click here to view page 4 of the table.

Consider a test of coordination that has a normal distribution, a mean of 50, and a standard deviation of 5. (a) How high a score would a person need to have to be in the top 3%? (b) Explain your answer to someone who has never had a course in statistics. Click here to view page 1 of the table. Click here to view page 2 of the table. Click here to view page 3 of the table. Click here to view page 4 of the table.

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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**Problem Statement:** Consider a test of coordination that has a normal distribution, a mean of 50, and a standard deviation of 5. **(a)** How high a score would a person need to have to be in the top 3%? **(b)** Explain your answer to someone who has never had a course in statistics. **Links to Table Pages:** - [Click here to view page 1 of the table.](#) - [Click here to view page 2 of the table.](#) - [Click here to view page 3 of the table.](#) - [Click here to view page 4 of the table.](#) **Explanation for Part (b):** To be in the top 3% of the scores, we need to find the score corresponding to the 97th percentile of the normal distribution, which has a mean (average) of 50 and a standard deviation of 5. This means that 97% of the scores are below this value, and 3% are above it. We find this score using a statistical table called the "z-table," which tells us how many standard deviations away from the mean we need to be to cover a given percentage. Once we find the value in the z-table, we use it to calculate the actual score by multiplying it by the standard deviation and adding it to the mean.
Transcribed Image Text:**Problem Statement:** Consider a test of coordination that has a normal distribution, a mean of 50, and a standard deviation of 5. **(a)** How high a score would a person need to have to be in the top 3%? **(b)** Explain your answer to someone who has never had a course in statistics. **Links to Table Pages:** - [Click here to view page 1 of the table.](#) - [Click here to view page 2 of the table.](#) - [Click here to view page 3 of the table.](#) - [Click here to view page 4 of the table.](#) **Explanation for Part (b):** To be in the top 3% of the scores, we need to find the score corresponding to the 97th percentile of the normal distribution, which has a mean (average) of 50 and a standard deviation of 5. This means that 97% of the scores are below this value, and 3% are above it. We find this score using a statistical table called the "z-table," which tells us how many standard deviations away from the mean we need to be to cover a given percentage. Once we find the value in the z-table, we use it to calculate the actual score by multiplying it by the standard deviation and adding it to the mean.
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