Question HelpA genetic experiment with peas resulted in one sample of offspring that consisted of 420 green peas and 152 yellow peas.a. Construct a 95% confidence interval to estimate of the percentage of yellow peas.b. It was expected that 25% of the offs pring peas would be yellowGiven that the percentage of offspring yellow peas is not 25%, do the results contradict expectations?a. Construct a 95% confidence interval. Express the percentages in decimal form.(Round to three decimal places as needed.)

a).The formula for 95% confidence interval estimate of the percentage of yellow peas is given below:

Answered: Question Help A genetic experiment with…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A genetic experiment with peas resulted in one sample of offspring that consisted of 421 green peas and 157 yellow peas. a. Construct a 90% confidence interval to estimate of the percentage of yellow peas. b. It was expected that 25% of the offspring peas would be yellow. Given that the percentage of offspring yellow peas is not 25%, do the results contradict expectations? a. Construct a 90% confidence interval. Express the percentages in decimal form. enter your response here<p<enter your response here (Round to three decimal places as needed.) b. Given that the percentage of offspring yellow peas is not 25%, do the results contradict expectations? Yes, the confidence interval does not include 0.25, so the true percentage could not equal 25% No, the confidence interval includes 0.25, so the true percentage could easily equal 25%
In a recent Zogby International Poll, nine of 48 respondents rated the likelihood of a terrorist attack in their community as “likely” or “very likely”. Use the “plus four” method to create a 98% confidence interval for the proportion of American adults who believe that a terrorist attack in their community is likely or very likely. Interpret your confidence interval.
A university planner wants to determine the proportion of undergraduate students who plan to attend graduate school. She surveys 54 current students and finds that 27 would like to continue their education in graduate school. Which of the following is the correct 90% confidence interval estimate for the proportion of undergraduates who plan to attend graduate school?
A genetic experiment with peas resulted in one sample of offspring that consisted of 445 green peas and 168 yellow peas. a. Construct a 90% confidence interval to estimate of the percentage of yellow peas. b. It was expected that 25% of the offspring peas would be yellow. Given that the percentage of offspring yellow peas is not 25%, do the results contradict expectations? a. Construct a 90% confidence interval. Express the percentages in decimal form. (Round to three decimal places as needed.)
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A survey was conducted where 27 students were asked which social media app is their favorite, Twitter or Tiktok. male female twitter 4 4 TikTok 4 15 create and interpret (in context) a one-proportion confidence interval. You may choose the level of confidence. conduct a Chi-Squared test for Association to determine if your data provide statistically significant evidence of an association between your two variables.
A researcher collected data on the annual salary of doctors in Illinois.He wishes to construct a confidence interval for the mean annual salary. Which of the following are true? I. A 98% confidence interval will have a greater chance of including the true mean salary than a 95% confidence interval.II. A 98% confidence interval will be narrower than a 95% confidence interval.III. A 98% confidence interval requires the researcher to take a larger sample. Choose the best answer below: A, II, III B. I C. III D. I, II E. II
Please answer the attached question. Thanks.
Tonya wants to estimate what proportion of her school's seniors plan to attend the prom. She interviews an SRS of 50 of the 750 seniors in her school and finds that 36 plan to go to the prom. Tonya then calculates a 90% confidence interval of (0.616, 0.824). Interpret Tonya's interval in context. 90% of the seniors at Tonya's high school are between 61.6% and 82.4% likely to attend prom. We can be 90% confident that the sample proportion is captured by the confidence interval. We are 90% confident that the interval from 0.616 to 0.824 captures the true proportion of all seniors at Tonya's high school who plan to attend the prom. O If Tonya took many samples, 90% of them would find that 72.4% of the seniors in the sample plan on attending prom. The percent of seniors at Tonya's high school who plan to attend the prom is certain to be between 61.6% and 82.4%. terms of use contact us help careers privacy policy about us
A genetic experiment with peas resulted in one sample of offspring that consisted of 405 green peas and 156 yellow peas. a. Construct a 90% confidence interval to estimate of the percentage of yellow peas. b. It was expected that 25% of the offspring peas would be yellow. Given that the percentage of offspring yellow peas is not 25%, do the results contradict expectations? a. Construct a 90% confidence interval. Express the percentages in decimal form. nothing<p<nothing (Round to three decimal places as needed.) b. Given that the percentage of offspring yellow peas is not 25%, do the results contradict expectations? No, the confidence interval includes 0.25, so the true percentage could easily equal 25% Yes, the confidence interval does not include 0.25, so the true percentage could not equal 25% Click to select your answer(s).
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A newspaper infographic titled "Social Media Jeopardizing Your Job?" summarized data from a survey of 1,850 recruiters and human resource professionals. The infographic indicated that 52% of the people surveyed had reconsidered a job candidate based on his or her social media profile. Assume that the sample is representative of the population of recruiters and human resource professionals in the United States. Would a 90% confidence interval be wider or narrower than the 95% confidence interval from part (a)? widernarrower

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