Tonya wants to estimate what proportion of her school's seniors plan to attend the prom. She interviews an SRS of 5C the 750 seniors in her school and finds that 36 plan to go to the prom. Tonya then calculates a 90% confidence interva (0.616, 0.824). Interpret Tonya's interval in context. 90% of the seniors at Tonya's high school are between 61.6% and 82.4% likely to attend prom. We can be 90% confident that the sample proportion is captured by the confidence interval. We are 90% confident that the interval from 0.616 to 0.824 captures the true proportion of all seniors at Tonya's high school who plan to attend the prom. O If Tonya took many samples, 90% of them would find that 72.4% of the seniors in the sample plan on attending prom.

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Tonya wants to estimate what proportion of her school's seniors plan to attend the prom. She interviews an SRS of 50 of
the 750 seniors in her school and finds that 36 plan to go to the prom. Tonya then calculates a 90% confidence interval of
(0.616, 0.824).
Interpret Tonya's interval in context.
90% of the seniors at Tonya's high school are between 61.6% and 82.4% likely to attend prom.
We can be 90% confident that the sample proportion is captured by the confidence interval.
We are 90% confident that the interval from 0.616 to 0.824 captures the true proportion of all seniors at Tonya's high
school who plan to attend the prom.
O If Tonya took many samples, 90% of them would find that 72.4% of the seniors in the sample plan on attending
prom.
The percent of seniors at Tonya's high school who plan to attend the prom is certain to be between 61.6% and 82.4%.
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Transcribed Image Text:Tonya wants to estimate what proportion of her school's seniors plan to attend the prom. She interviews an SRS of 50 of the 750 seniors in her school and finds that 36 plan to go to the prom. Tonya then calculates a 90% confidence interval of (0.616, 0.824). Interpret Tonya's interval in context. 90% of the seniors at Tonya's high school are between 61.6% and 82.4% likely to attend prom. We can be 90% confident that the sample proportion is captured by the confidence interval. We are 90% confident that the interval from 0.616 to 0.824 captures the true proportion of all seniors at Tonya's high school who plan to attend the prom. O If Tonya took many samples, 90% of them would find that 72.4% of the seniors in the sample plan on attending prom. The percent of seniors at Tonya's high school who plan to attend the prom is certain to be between 61.6% and 82.4%. terms of use contact us help careers privacy policy about us
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