Question 8Find the AH (in kJ) for the reaction below, given the following reactions and subsequent AH values:C3H8(g) + 5 O2(g) → 3 CO2(g) + 4 H20(g)3 C(s) + 4 H2(g) C3H8(g)AH = – 118.2 kJ.C(s) + 02(g) – CO2(g)AH = – 62.4 kJH2(g) + 1/2 O2(g) – H20(g)AH = – 182.5 kJ(round off final answer to 1 decimal place)

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Quéstion 8 Find the AH (in kJ) for the reaction below, given the following reactions and subsequent AH values: C3H8(g) + 5 02(g) → 3 CO2(g) + 4 H2O(g) 3 C(s) + 4 H2(g) –C3H8(g) AH =- 118.2 kJ C(s) + 02(g) - Co2(g) AH =- 62.4 kJ H2(g) + 1/2 02(g) - H20(g) AH =- 182.5 kJ (round off final answer to 1 decimal place)

Quéstion 8 Find the AH (in kJ) for the reaction below, given the following reactions and subsequent AH values: C3H8(g) + 5 02(g) → 3 CO2(g) + 4 H2O(g) 3 C(s) + 4 H2(g) –C3H8(g) AH =- 118.2 kJ C(s) + 02(g) - Co2(g) AH =- 62.4 kJ H2(g) + 1/2 02(g) - H20(g) AH =- 182.5 kJ (round off final answer to 1 decimal place)

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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BE’s are: C=O 799, C–H 413, O–H 467, O–O 498, H–H 432 kJ/mol CO2(g) + 4H2(g) → CH4(g) + 2H2O(g) ΔHrxn° = ___ kJ (from ΔHf°s) ΔHrxn°(BE) = ___ kJ (from BEs) = (2x799+432-4x413-4x467) CH4(g) + 2O2(g) → CO2(g) + 2H2O(g) ΔHrxn° = ___ kJ (from ΔHf°s) ΔHrxn°(BE) = ___ kJ (from BEs) ...Calculate ΔHrxn°s from both!
A Moving to another question will save this response. Question 2 "A new element (Rr) has been synthesized and its properties analyzed. When 0.132g of RrO (s) is added to 166g of water at 24° Cin a coffee cup calorimeter, the following reaction occurs. RrO(s) + H 20(1) – Rr(OH) 2 (aq) AH = -74.8kJ/mol Given the molar mass for RrO is 62g/mol calculate the following moles of Rro round answer to 4 decimal places omit trailing zeroes 9 rxn in joules round answer to the nearest whole number 9 water in joules round answer to the nearest whole number Final temperature round answer to 1 decimal place omit trailing zeroes A Moving to another question will save this response. Chip
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QUESTION 18 PLEASE
Find the AH (in kilojoules) for the reaction below, given the following reactions and subsequent AH values: (Write your answer in 1 decimal place without the unit). N2(g) + 202(g) – 2NO 2(g) N2(g) + 3H2(g) 2NH3(g) AH = -115 kJ 2NH3(g) + 4H20(1) → 2NO2(g) + 7H2(g) AH = -142.5 kJ H20(1) H2(g) + 1/20 2(g) AH = -43.7 kJ
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