THERMODYNAMICS: Given the following hypothetical thermochemical equations: 2QJ3 (g) + 3Q2X (g) 4Q2 (g) + 3J2X (I) AH = -1,000.7 kJ 4QJ3 (g) + 3X2 (g) 2Q2 (g) + 6J2X (I) AH = -1,548.9 kJ Calculate the value of AH (in kJ) for the reaction: Q2 (g) + ½ X2 (g)Q2X (g) (Round off the final answer to ONE decimal place. Do not include unit.)

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Question 7
THERMODYNAMICS: Given the following hypothetical thermochemical equations:
2QJ3 (g) + 3Q2X (g) 4Q2 (g) + 3J2X (1)
AH = -1,000.7 kJ
4QJ3 (g) + 3X2 (g)→ 202 (0) + 6J2X (1)
AH = -1,548.9 kJ
Calculate the value of AH (in kJ) for the reaction:
Q2 (g) + ½ X2 (g) Q2X (g)
(Round off the final answer to ONE decimal place. Do not include unit.)
Transcribed Image Text:Question 7 THERMODYNAMICS: Given the following hypothetical thermochemical equations: 2QJ3 (g) + 3Q2X (g) 4Q2 (g) + 3J2X (1) AH = -1,000.7 kJ 4QJ3 (g) + 3X2 (g)→ 202 (0) + 6J2X (1) AH = -1,548.9 kJ Calculate the value of AH (in kJ) for the reaction: Q2 (g) + ½ X2 (g) Q2X (g) (Round off the final answer to ONE decimal place. Do not include unit.)
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