Rate5287153663918155274419765882785596866044989471026515474728796493526919112230451955945343823617645466136122647838169835115734742855433261027923779636599861852349138080475811536747315534225526455064808436836825816014933726138363901053816936152444695597430920607996452506376282 Question 8An email filter is planned to separate valid e-mails from spam. The word free occurs in 90% ofthe spam messages and only 1% of the valid messages. Also, 10% of the messages are spam.Determine the probability that the message contains free given that it is valid (round youranswer to 4 decimals)

Solution The probability that the messages contains free is given as:

Answered: Question 8 An email filter is planned…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Minutes 28 24 37 32 34 32 31 34 25 23 32 24 23 39 24 40 23 35 31 26 27 36 27 21 25 34 24 33 28 27 38 35 36 28 36 38 34 33 32 30 31 30 30 19 30 24 28 22 30 21 21 28 33 24 39 38 27 35 34 28 18 19 29 31 38 28 33 22 25 49 24 33 21 38 31 32 26 31 33 30 32 31 31 31 39 34 39 28 32 36 30 29 29 27 24 34 26 20 32 32 34 25 21 32 37 28 25 22 41 28 Above is the excel data and use excel to solve with explanation and write a conclusion at the end, thanks
Point A(7, 17); Point B(19, 2) 20 19 18 17 16 15 14 13 12 11 10 9 8 7. 5 4. 3 2 01 2 345 6 7 89 10 11 12 13 14 15 16 17 18 19 20 10
The accompanying data are 45 commute times to work in minutes for workers of age 16 or older in Chicago. Construct a frequency distribution. Use a class width of 15 minutes and begin with a lower class limit of 0 minutes. Do the data amounts appear to have a normal distribution? Examine the data and identify anything appearing to be unique. Click the icon to view the commute times. ..... Construct the frequency distribution. Commute Time Frequency (minutes) 0- (Type whole numbers.) Do the data amounts appear to have a normal distribution? O A. No, because the frequencies start at a maximum and become low, and because the distribution is not symmetric. B. No, because while the frequencies start low, proceed to one or two high frequencies, then decrease to a low frequency, the distribution is not symmetric. C. Yes, because the frequencies start low, proceed to one or two high frequencies, then decrease to a low frequency, and the distribution is approximately symmetric. D. No, because…
Price SqFt 600000 2767 545000 2731 314900 2051 419000 2084 365000 2270 479000 1950 323000 1235 339900 2116 399000 1644 552000 2415 223017 1375 315777 1529 499000 2223 575000 2327 342000 1879 375000 1558 349000 2012 485000 1200 549888 1410 295000 1943 399000 1827 306999 1840 265200 1636 479000 2357 249700 1152 539500 2650 365000 2154 295900 1279 499000 2156 526000 2493 514900 2390 346000 1347 460000 2120 389000 1917 499000 1200 405000 2643 389900 1789 545000 2327 339000 1742 425000 1746 479000 1421 392000 2569 Can square feet explain prices? Provide evidence to support your answer. If the square feet is 2418, what is the expected price for the home? Please include the excel function.
An experiment was performed to determine whether different types of chocolate take different amounts of time to dissolve. Forty people were divided into five groups. Each group was assigned a certain type of chocolate. Each person dissolved one piece of chocolate, and the dissolve time (in seconds) was recorded. For comparison, each person in each group also dissolved one piece of butterscotch candy; these pieces were identical for all groups. The data, which include the group, the dissolve times for both chocolate and butterscotch, the difference between the dissolve times, and the ratio of the dissolve times, are presented in the following table. Note that the design is slightly unbalanced; group 3 has nine people and group 5 has only seven. Group Chocolate Butterscotch Difference Ratio 60 135 75 2.25 865 635 230 1.36 122 63 59 1.94 110 75 35 1.47 71 37 34 1.92 81 58 23 1.40 2405 1105 1300 2.18
Interpret the Coefficient of Determination New Cases New Deaths 1765 4 1097 5 891 4 959 6 937 58 1047 26 1353 9 1776 8 1952 34 1906 8 2052 11 1524 139 1453 146 1912 40 2048 137 2058 8 1895 11 2163 14 1357 69 1862 64 1783 74 2178 20 1797 54 1949 53 1581 50 1173 94 2245 95 1169 71 1849 48 2109 71 2103 80 1658 58 1583 67 1266 68 1590 55 1894 61 1941 52 1790 70 1690 52 1235 65 1345 114 1734 68 2022 26 1960 12 1928 8 1685 2 1391 7 1184 53 1744 96 1901 157 2240 239 1888 20 2288 6 1414 16 1557 22 2269 72 2651 46 2921 42 2113 29 2037 4 2067 47 1783 20 2452 15 3045 19 3439 42 3276 51 3356 5 2668 7 2886 17 3749 63 4578 87 5000 72 4899 63 5404 8 4437 11 4387 18 5290 21 7103 13 7999 30 7757 39 8019 4 5867 20 6666 47 8773 56 9838 54 9595 10 9475 11 10016 16 9296 5 6128 106
ID Cost of Airfares in the US (domestic) 1 146 2 620 3 79 4 299 5 576 6 89 7 589 8 165 9 509 10 23 11 376 12 226 13 462 14 634 15 36 16 226 17 263 18 456 19 390 20 541 21 19 22 329 23 537 24 512 25 423 26 515 27 358 28 110 29 319 30 671 31 561 32 96 33 574 34 385 35 263 36 240 37 449 38 592 39 404 40 119 41 173 42 419 43 495 44 224 45 228 46 616 47 168 48 396 49 524 What if the probability that a domestic airfare is between $300 and $400? What is the cost for the 3% highest domestic airfares? Use Excel functions Dist and Norm.INV to check your answers in Question 2-5.
Test Nondefective 79 93 81 93 79 94 79 91 76 94 81 94 79 94 79 92 82 93 86 93 83 92 78 95 77 92 77 93 80 95 73 95 87 95 75 93 82 96 74 93 81 95 81 95 82 94 73 94 75 94 82 92 87 95 84 94 86 94 79 94 82 95 70 92 86 96 84 94 75 95 75 95 77 93 78 95 76 95 84 94 76 94 78 94 81 94 79 94 78 94 above is excel data and please solve the excel part with formulas and explanation, thanks
F, C, D, C, D, B, D, A, D, D, B, B, B, B, D, D, B, B, F, A, F Grade A frequency: Grade B frequency = Grade C frequency: = Grade D frequency =_ Grade E frequency Grade F frequency = Blank # 1 Blank # 2 Blank # 3 Blank # 4 Blank # 5 = = >> N N
Number of ChildrenTable 1 shows the number of women (per 1000) between 15 and 50 years of age who have been married grouped by the number of children they have had. Table 2 gives the same information for women who have never been married.1 Number of Children Women per 1000 0 162 1 213 2 344 3 182 4 69 5+ 32 Table 1 Women who have been married Number of Children Women per 1000 0 752 1 117 2 72 3 35 4 15 5+ 10 Table 2 Women who have never been married 1http://www.census.gov/hhes/fertility/data/cps/2014.html, Table 1, June 2014. Condition gt requires numbers instead of "null" and "0" (a) Without doing any calculations, which of the two samples appears to have the highest mean number of children? Women who have been marriedWomen who have never been married Which of the distributions appears to have the mean most different from the median? Women who have been marriedWomen who have never been married…
ID Old Score New Score 1 81 82 2 72 72 3 77 74 4 74 72 5 78 78 6 77 72 7 83 84 8 90 86 9 70 69 10 70 72 11 72 69 12 71 69 13 71 67 14 71 64 15 71 68 16 71 69 17 71 71 18 71 69 19 71 72 20 71 70 21 71 71 22 71 71 23 72 70 24 72 69 25 72 72 26 72 73 27 72 74 28 72 69 29 72 73 30 72 69 31 73 71 32 73 74 33 73 72 34 73 75 35 73 73 36 73 69 37 73 72 38 74 67 39 74 68 40 74 75 41 74 74 42 74 75 43 74 74 44 74 68 45 74 70 46 75 70 47 75 72 48 75 70 49 75 69 50 75 74 51 75 71 52 75 71 53 75 71 54 75 71 55 75 69 56 76 75 57 76 70 58 76 70 59 76 78 60 76 72 61 77 78 62 77 73 63 77 74 64 77 78 65 78 78 66 78 71 67 78 72 68 79 72 69 79 76 70 79 77 71 79 77 72 80 82 73 80 74 74 81 81 75 82 82 Question 13 with the data set above.
The accompanying data are 45 commute times to work in minutes for workers of age 16 or older in Chicago. Construct a frequency distribution. Use a class width of 15 minutes and begin with a lower class limit of 0 minutes. Do the data amounts appear to have a normal distribution? Examine the data and identify anything appearing to be unique. Click the icon to view the commute times. Frequency Time (minutes) 0-14 4 15-29 15 30-44 11 45-59 9 60-74 75-89 5 1 (Type whole numbers.) Do the data amounts appear to have a normal distribution? OA. No, because while the distribution is approximately symmetric, the frequencies start at a maximum and become low. B. No, because while the frequencies start low, proceed to one or two high frequencies, then decrease to a low frequency, the distribution is not symmetric. OC. Yes, because the frequencies start low, proceed to one or two high frequencies, then decrease to a low frequency, and the distribution is approximately symmetric. OD. No, because the…

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