Question 8, 7.3.15-T = Homework: Week 4: Unit 7 HW Score: 69.73%, 58.57 of 84 points O Points: 8 of 12 Part 5 of 5 Save A marketing survey is conducted in which students are to taste two different brands of soft drink. Their task is to correctly identify the brand tasted. A random sample of 190 students is taken. Assume that the students have no ability to distinguish between the two brands. Complete (a) through (d) below. There is a 90% probability that the sample percentage will be contained within 6.0 % symmetrically around the population percentage. (Round to the one decimal place as needed.) c. What is the probability that the sample percentage of correct identifications is greater than 55%? 0.0838 (Round to four decimal places as needed.) d. Which is more likely to occur-more than 62% correct identifications in a sample of 190 or more than 56% correct identifications in a sample of 1,000? Explain. Define more than 62% correct identifications in a sample of 190 as event 1, and define more than 56% correct identifications in a sample of 1,000 as event 2. O A. They are equally likely. O B. Event 1 is more likely because the Z-value for it is less than the Z-value for event 2, and therefore its probability is greater than that of event 2. OC. Event 2 is more likely because the Z-value for it is greater than the Z-value for event 1, and therefore its probability is greater than that of event 1 O D. It cannot be determined from the information given.

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Transcribed Image Text:Question 8, 7.3.15-T > HW Score: 69.73%, 58.57 of 84 points 2 Points: 8 of 12 Homework: Week 4: Unit 7 Part 5 of 5 Save A marketing survey is conducted in which students are to taste two different brands of soft drink. Their task is to correctly identify the brand tasted. A random sample of 190 students is taken. Assume that the students have no ability to distinguish between the two brands. Complete (a) through (d) below. There is a 90% probability that the sample percentage will be contained within 6.0 % symmetrically around the population percentage. (Round to the one decimal place as needed.) c. What is the probability that the sample percentage of correct identifications is greater than 55%? 0.0838 (Round to four decimal places as needed.) d. Which is more likely to occur-more than 62% correct identifications in a sample of 190 or more than 56% correct identifications in a sample of 1,000? Explain. Define more than 62% correct identifications in a sample of 190 as event 1, and define more than 56% correct identifications in a sample of 1,000 as event 2. O A. They are equally likely. B. Event 1 is more likely because the Z-value for it is less than the Z-value for event 2, and therefore its probability is greater than that of event 2. OC. Event 2 is more likely because the Z-value for it is greater than the Z-value for event 1, and therefore its probability is greater than that of event 1. O D. It cannot be determined from the information given.

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