Question 6: Give the individual reaction orders for all substances and the overall reaction order from the following rate law: Rate = k [BrO3–] [Br–] [H+]2 [BrO3–] = [Br–] = [H+]2 = overall = This is the answer to 6: The overall order of the substance is the sum of powers of reactant appearing in the rate law. Expression Rate = [BrO3] = 1 [Br-] = 1 [H+]2= 2 Overall Order = 1+1+2 = 4 The reaction is of the 4th order with the given mechanism. I need help with the question below: By what factor does the rate in question 6 change if each of the following changes occurs individually a) BrO3– is doubled b) Br– is halved c) H+ is quadrupled
Question 6:
Give the individual reaction orders for all substances and the overall reaction order from the following rate law:
Rate = k [BrO3–] [Br–] [H+]2
[BrO3–] = [Br–] = [H+]2 = overall =
This is the answer to 6:
The overall order of the substance is the sum of powers of reactant appearing in the rate law.
Expression
Rate =
[BrO3] = 1
[Br-] = 1
[H+]2= 2
Overall Order = 1+1+2 = 4
The reaction is of the 4th order with the given mechanism.
I need help with the question below:
By what factor does the rate in question 6 change if each of the following changes occurs individually
a) BrO3– is doubled
b) Br– is halved
c) H+ is quadrupled
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