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What is the rate constant of a first-order reaction that takes 490 seconds for the reactant concentration to drop to half of its initial value? Express your answer with the appropriate units. • View Available Hint(s) Reset Templates Symbols undo rego keyboard shortcuts help Value Units

What is the rate constant of a first-order reaction that takes 490 seconds for the reactant concentration to drop to half of its initial value? Express your answer with the appropriate units. • View Available Hint(s) Reset Templates Symbols undo rego keyboard shortcuts help Value Units

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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What is the rate constant of a first-order reaction that takes 490 seconds for the reactant concentration to drop to half of its initial value? Express your answer with the appropriate units. • View Available Hint(s) Zeset Templates Symbols undo redlo keyboard shortcuts help Value Units
Transcribed Image Text:What is the rate constant of a first-order reaction that takes 490 seconds for the reactant concentration to drop to half of its initial value? Express your answer with the appropriate units. • View Available Hint(s) Zeset Templates Symbols undo redlo keyboard shortcuts help Value Units
The integrated rate law allows chemists to predict the reactant concentration after a certain amount of time, or the time it would take for a certain concentration to be reached. The integrated rate law for a first-order reaction is: Half-life equation for first-order reactions: 0.693 t1/2 = [A] = [A]oe-kt where t/2 is the half-life in seconds (s), and k is the rate constant in inverse seconds (s). Now say we are particularly interested in the time it would take for the concentration to become one- [A], half of its initial value. Then we could substitute " for [A] and rearrange the equation to: 0.693 t1/2 This equation calculates the time required for the reactant concentration to drop to half its initial value. In other words, it calculates the half-life.
Transcribed Image Text:The integrated rate law allows chemists to predict the reactant concentration after a certain amount of time, or the time it would take for a certain concentration to be reached. The integrated rate law for a first-order reaction is: Half-life equation for first-order reactions: 0.693 t1/2 = [A] = [A]oe-kt where t/2 is the half-life in seconds (s), and k is the rate constant in inverse seconds (s). Now say we are particularly interested in the time it would take for the concentration to become one- [A], half of its initial value. Then we could substitute " for [A] and rearrange the equation to: 0.693 t1/2 This equation calculates the time required for the reactant concentration to drop to half its initial value. In other words, it calculates the half-life.
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